Use linear approximation, i.e. the tangent line, to approximate Let f(x) = X 1 0.501 and find the equation of the tangent line to f(x) at a "nice" point near 0.501. c) Now use this equation to approximate as follows: a) What is a "nice" x-value, (one that is easy to evaluate), close to 0.501? b) What is the linearization (tangent line equation) at that x-value? (Use L(x) ) 1 0.501

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