Use Cahn-Ingold-Prelog rules on the molecule below and highlight the highest priority substituent red, second priority blue, and third priority green. In your answer, be sure to highlight the entire substituent. Key: 1 (Highest Priority) = Red 2 (Second Priority)= Blue 3 (Third Priority)= Green Br X

According to Cahn-Ingold-Prelog the priority of substituents as per following rules.

1. Rank all directly attached atom to chiral center as per their atomic number,here Br has highest atomic number than C so Br goes to first priority.

2.If Directly attached atom is same then consider next atom and prioritize according to their atomic number, here Methyl,Ethyl and alkene C=C propene group out of these C=C ethylene goes to second,ethyl goes to third and methyl on last means fourth priority.

1) Highest Priority = Br= Red

2) Second Priority =Etylene =Blue

2) Third Priority =Ethyl =Green