Use Cahn-Ingold-Prelog rules on the molecule below and highlight the highest priority substituent red, second priority blue, and third priority green. In your answer, be sure to highlight the entire substituent. Key: 1 (Highest Priority) = Red 2 (Second Priority)= Blue 3 (Third Priority)= Green Br X

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Use Cahn-Ingold-Prelog rules on the molecule below and highlight the highest priority substituent red, second priority blue, and third priority green. In your
answer, be sure to highlight the entire substituent
Key:
1 (Highest Priority) = Red
2 (Second Priority)= Blue
3 (Third Priority) = Green
-
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Transcribed Image Text:ctrl Use Cahn-Ingold-Prelog rules on the molecule below and highlight the highest priority substituent red, second priority blue, and third priority green. In your answer, be sure to highlight the entire substituent Key: 1 (Highest Priority) = Red 2 (Second Priority)= Blue 3 (Third Priority) = Green - Using Cann-Ingold-Prelog priority rules for small organic... Shift + BO'F Sunny cal caps lock In Explanation --- "? 7 O A Z -- B Check د Bri المال الالالالالالا الالالالالالالال الاكل الالال S "3 $4 965 5 W ER H Q Search OF T & 7 ••• lip N لالالا ه 8 X B Ⓒ2023 McGraw H LLC. All Rights Reserved. Terms of Use Privacy Center I Accessibility 14 5 0 alt ا JE prt sc ------- . enter dalate T shift home olo po up intel CORE Ar 15 Do dn ? 6:11 PM 2/23/2023 BANG & OLUFSEN intel IRIS end GRAPHICS
Expert Solution
Step 1

According to Cahn-Ingold-Prelog the priority of substituents as per following rules.

1. Rank all directly attached atom to chiral center as per their atomic number,here Br has highest atomic number than C so Br goes to first priority.

2.If Directly attached atom is same then consider next atom and prioritize according to their atomic number, here Methyl,Ethyl and alkene C=C propene group out of these C=C ethylene goes to second,ethyl goes to third and methyl on last means fourth priority.

1) Highest Priority = Br= Red

2) Second Priority =Etylene =Blue

2) Third Priority =Ethyl =Green

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