Use a table of areas to find each of the shaded areas under the Standard Normal Distribution. (a) (b) (c) -1.49 0 0 0.57 1.96 2.61

Sketch the normal distribution with a. µ = -2 and σ = 2.b. µ = -2 and σ = 1/2.c. µ = 0 and σ = 2.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2= -0.81 z=1.21 The area of the shaded region is (Round to four decimal places as needed.)

In each part, find the area under the standard normal curve that lies between the specified z-score, sketch a standard normal curve, and shade the area of interest. b. -2 and 2 c. - 3 and 3 a. - 1 and 1 a. Find the area under the standard normal curve that lies between - 1 and 1, sketch a standard normal curve, and shade the area of interest. The area under the standard normal curve that lies between - 1 and 1 is (Type an integer or decimal rounded to four decimal places as needed.)

For each z score that follows, find the percentage of scores at that value or higher in the normal distribution: + 1.67 -2.02 + 0.08

In the normal distribution (the area under the normal curve): The area (at and) below the mean (z = 0.00) is % ___.  of the area. The area between z = -1.00 and z = +1.00 is approximately ____.  % of the area. The area between z = +1.00 and z = +2.00 is approximately  _____. % of the area. The area between z = -2.00 and z = +2.00 is approximately  ____ % of the area.