Use a definite integral to find the area under the curve between the given x-values. f(x) = 6 Make a sketch of the curve showing the region. 5 4 3 2 1 O y 6 5 4 3 2 1 O from x= 1 to x = 6 square units 1 1 2 3 2 3 4 4 5 6 6 2 1 1 2 3 4 5 6 2 1 O 1 2 3 4 5 X

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter7: Integration
Section7.4: The Fundamental Theorem Of Calculus
Problem 6YT: YOUR TURN Find the area under the curve y=sec2(x/3) between x= and x=.
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Use a definite integral to find the area under the curve between the given x-values.
6
5
Make a sketch of the curve showing the region.
y
4
3
2
6
5
4
3
1
=
1
from x 1 to x = 6
square units
2
2
3
4 5
6
y
61
5
4
3
2
1
DO
1
2
3
4
5
6
y
6
5
4
3
2
1
2
3
5
X
@
Transcribed Image Text:Use a definite integral to find the area under the curve between the given x-values. 6 5 Make a sketch of the curve showing the region. y 4 3 2 6 5 4 3 1 = 1 from x 1 to x = 6 square units 2 2 3 4 5 6 y 61 5 4 3 2 1 DO 1 2 3 4 5 6 y 6 5 4 3 2 1 2 3 5 X @
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