Homework Help is Here – Start Your Trial Now!
Math
Calculus
Use a change of variables or the table to evaluate the following indefinite integral. √x³ (x²-5) d dx Click the icon to view the table of general integration formulas. √x³ (x²-5) dx = 0 General Integration Formulas I

Use a change of variables or the table to evaluate the following indefinite integral. √x³ (x²-5) d dx Click the icon to view the table of general integration formulas. √x³ (x²-5) dx = 0 General Integration Formulas I

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter8: Further Techniques And Applications Of Integration
Section8.2: Integration By Parts
Problem 34E
See similar textbooks
icon
Related questions
Question
F Use a change of variables or the table to evaluate the following indefinite integral. √x³ (x²-5) d dx Click the icon to view the table of general integration formulas. √x²³(x²-5) = dx General Integration Formulas 1 cos ax dx = -s a sec ax dx: _dx sec ax tan ax dx = a +x √√²-1²² +0 +C S- sin ax + C dx 2 x√x². 1 a a tan ax + C 1 - tan a 1 a 1 a sec ax + C -1 X a sec +C ¹||+ + C, a>0 1 sin ax dx=-cos ax + C a 1 csc²ax dx=-cot ax + C a D csc ax cot ax dx = - dx √₂² 1 Sbxdx=b+C, b>0, b#1 In b X a csc ax + C == sin ¹+C, a>0 - X
Transcribed Image Text:F Use a change of variables or the table to evaluate the following indefinite integral. √x³ (x²-5) d dx Click the icon to view the table of general integration formulas. √x²³(x²-5) = dx General Integration Formulas 1 cos ax dx = -s a sec ax dx: _dx sec ax tan ax dx = a +x √√²-1²² +0 +C S- sin ax + C dx 2 x√x². 1 a a tan ax + C 1 - tan a 1 a 1 a sec ax + C -1 X a sec +C ¹||+ + C, a>0 1 sin ax dx=-cos ax + C a 1 csc²ax dx=-cot ax + C a D csc ax cot ax dx = - dx √₂² 1 Sbxdx=b+C, b>0, b#1 In b X a csc ax + C == sin ¹+C, a>0 - X
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer