USA Today (February 16, 2012) reported that the percentage of U.S. residents living in poverty was 12.5% for men and 15.1% for women. These percentages were estimates based on data from large representative samples of men and women. For purposes of this exercise, suppose that the sample sizes were 1200 for the sample of men and 1000 for the sample of women. Use the survey data to compute a 90% confidence interval for the difference in the proportion living in poverty for men and women. (Use Pmen - Pwomen' Round your answers to three decimal places.) ( Interpret the interval. ○ We are 90% confident that the true mean proportion living in poverty for men is between these two values. We are 90% confident that the true difference in the proportions living in poverty for men and women is between these two values. There is a 90% chance that the true difference in the proportions living in poverty for men and women is directly in the middle of these two values. We are 90% confident that the true mean proportion living in poverty for women is between these two values. There is a 90% chance that the true mean proportion living in poverty for men is directly in the middle of these two values.

A: here use Empirical rule

A: The given expression is : 10p2-p-2 To factorize the given expression.

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A: a³−16a ⇒a(a²−16) ⇒a(a² −4²) ⇒a(a+4)(a−4)

A: I = ∫4x e−3x dx

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A: sec-11.5

A: we have to determine the value of z to correspondingprobability value is 0.0400

A: The point is, 6,-2 So, the point is in 4th quadrant.

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A: The given expression is

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A: The table is Gallons(g) Liters(l) 1 3.79 2 7.58 3 11.37 4 15.16 5 18.95 6 22.74…