
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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Question
![Upper and Lower Sums - Round Two
(a) Consider the following partition sequences for the interval [0, 1]:
Zn = (x0, x1, ..., xn), with xk = ½-½
Zn = (0, T1, T2, ..., Tn), with Ãk = 3
Determine the fineness measures | Z | and |Z❘ depending on n, as well as their limits for n → ∞,
and justify why Zn is unsuitable for determining the integral.
(b) Using the partition Z from (a), determine the integral
So √x dx.
Then slightly modify the partition and use it to determine the integral over the interval [0,6] for any
bЄ R.
Hint: You may use the summation formulas in this problem without proof:
ΣΕ
1 k² = n(n+1)(2n + 1)
and
1 k = n(n + 1).](https://content.bartleby.com/qna-images/question/d4d280bd-006f-4e5c-9dde-8a4aad9d221e/be939c9b-998e-4f8c-bd31-e36bba2434ba/t0kfbr_thumbnail.png)
Transcribed Image Text:Upper and Lower Sums - Round Two
(a) Consider the following partition sequences for the interval [0, 1]:
Zn = (x0, x1, ..., xn), with xk = ½-½
Zn = (0, T1, T2, ..., Tn), with Ãk = 3
Determine the fineness measures | Z | and |Z❘ depending on n, as well as their limits for n → ∞,
and justify why Zn is unsuitable for determining the integral.
(b) Using the partition Z from (a), determine the integral
So √x dx.
Then slightly modify the partition and use it to determine the integral over the interval [0,6] for any
bЄ R.
Hint: You may use the summation formulas in this problem without proof:
ΣΕ
1 k² = n(n+1)(2n + 1)
and
1 k = n(n + 1).
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