MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Please help with (d)

On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate? The file ResidentialWater contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities. Click on the datafile logo to reference the data. DATA file a. Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. Choose the correct null hypothesis: 1. Ho: μ = 21.62 2. Ho: : 3. Ho: 1 μ = 21.62 21.62 Choose the correct alternative hypothesis:
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Transcribed Image Text:On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate? The file ResidentialWater contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities. Click on the datafile logo to reference the data. DATA file a. Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. Choose the correct null hypothesis: 1. Ho: μ = 21.62 2. Ho: : 3. Ho: 1 μ = 21.62 21.62 Choose the correct alternative hypothesis:
2. H₂: 3. H₂: 1 = 21.62 <21.62 b. What is the p-value for your hypothesis test in part (a)? Round your answer to four decimal places. 0.2580 c. At a = 0.05, can your null hypothesis be rejected? What is your conclusion? the null hypothesis. The mean rate per 5 CCF of residential water throughout the U.S. significantly from the rate per 5 CCF of residential water in Tulsa. Do not reject does not differ d. Repeat the preceding hypothesis test using the critical value approach. The critical value(s) is(are) +/-2.02 t = (to 3 decimals), do not reject the null hypothesis.
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Transcribed Image Text:2. H₂: 3. H₂: 1 = 21.62 <21.62 b. What is the p-value for your hypothesis test in part (a)? Round your answer to four decimal places. 0.2580 c. At a = 0.05, can your null hypothesis be rejected? What is your conclusion? the null hypothesis. The mean rate per 5 CCF of residential water throughout the U.S. significantly from the rate per 5 CCF of residential water in Tulsa. Do not reject does not differ d. Repeat the preceding hypothesis test using the critical value approach. The critical value(s) is(are) +/-2.02 t = (to 3 decimals), do not reject the null hypothesis.
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