ucstion One In a tensile test, material mechanical properties are determined by relating deformations to the applice forces. i. Sketch a typical specimen used in such tests and on it indicate two important dimensions i Sketch the difference you would cxpect in tensile and compressive deformations ii Sketch a stress-strain curve/graph you would expect from such a test and on it indicate how yo would obtain (1) Young's modulus, E(2) elastic limit,oei(3) yield strength ay and (4) ultiman tensile strength dUTS In such a test, as the one in (a) above, a specimen manufactured from steel, and had an original diamete of 12.8 mm and gauge length of 50.8 mm. The resulting data, stress and strain, is listed in the table below. ain 0007 0018 005 0 052 0.056 0.065 0072 0076 0.15 017 022 024 a11 m) ess 50.8 218 540 600 630. 650 640 634 643 745 851 BAS 815 770 "Pa) By plotting stresses on the vertical axis and strains on the horizontal axis, plot a stress-strain curv and determine the following. a) Elastic limit b) Modulus of elasticity, c) Yield stress, A Minmate stress and rhe

ucstion One In a tensile test, material mechanical properties are determined by relating deformations to the applice forces. i. Sketch a typical specimen used in such tests and on it indicate two important dimensions i Sketch the difference you would cxpect in tensile and compressive deformations ii Sketch a stress-strain curve/graph you would expect from such a test and on it indicate how yo would obtain (1) Young's modulus, E(2) elastic limit,oei(3) yield strength ay and (4) ultiman tensile strength dUTS In such a test, as the one in (a) above, a specimen manufactured from steel, and had an original diamete of 12.8 mm and gauge length of 50.8 mm. The resulting data, stress and strain, is listed in the table below. ain 0007 0018 005 0 052 0.056 0.065 0072 0076 0.15 017 022 024 a11 m) ess 50.8 218 540 600 630. 650 640 634 643 745 851 BAS 815 770 "Pa) By plotting stresses on the vertical axis and strains on the horizontal axis, plot a stress-strain curv and determine the following. a) Elastic limit b) Modulus of elasticity, c) Yield stress, A Minmate stress and rhe

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Consider the graph below for 3 test samples A, B and C of the same metal composition which have been cold-worked, but to different extents. If you had to sort the samples by the degree of cold-working they have undergone, how would you rank them? Stress (MPa) 600 500 4006 300 200 100 0 A B 0.05 1 0.1 0.15 Strain Select the correct answer: a. A
1 The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 159 kN. - Length of the specimen is 22 mm. - The yield strength is 80 kN/mm². - The percentage of elongation is 40 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 15 kN, iv) Young's Modulus if the elongation is 2.8 mm at 15 kN and (v) Final diameter if the percentage of reduction in area is 20 %. Solution Initial Cross-sectional Area (in mm²) The Diameter of the Specimen (in mm) - น Final Length of the Specimen (in mm). 30 Stress at the elastic load (in N/mm²) 4⁰ Young's Modulus of the Specimen (in N/mm²) 5 Final Area of the Specimen at Fracture (in mm²) Final Diameter of the Specimen after Fracture (in mm)-
a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
The following data were recorded during the tensile test of a test specimen with a diameter of 12.8 mm. The gage length is 50.8 mm. The given data are as follow; Given: Test specimen material: Aluminum Diameter of test specimen: Do = 12.8 mm Length of test specimen: Lo = 50.8 mm Force and Elongation data for test specimen Assumptions: 1. The given data is accurate and the material is isotropic 2. The direction of applied force is parallel to the length of the cylinder Requirement: To interpret and plot the stress Vs Strain curve for a given specimen DATA: LENGTH, mm STRESS, MPa LOAD, N 0 50.8 7 330 50.851 15 100 50.902 23 100 50.952 30 400 51.003 34 400 51.054 38 400 51.308 41 300 51.816 44 800 52.832 46 200 53.848 47 300 54.864 47 500 55.88 36 100 56.896 44 800 57.658 42 600 58.42 36 400 59.182 STRAIN
The stress-strain data from a tensile test on a cast-iron specimen are € (10-3) 0 0.20 0.44 0.80 1.0 1.5 2.0 26 32 40 46 49 54 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 2.8 3.4 4.0 5.0 a (kpsi) 0 5 10 16 19 Determine the tangent modulus, E, at a value of a=0 psi. 106 psl. The tangent modulus, Eis X
hings The following results were obtained during a tensile test to destruction on a mild steel test piece of diameter 15.96mm and 80mm gauge length Extension for a load of 40KN = 0.08mm Maximum load applied during test = 93kN Diameter at fracture = 12.85mm %3D Final length between gauge points 106mm From these results, determine: i) The modulus of elasticity for mild steel ii) The tensile strength iii) Percentage of elongation iv) Percentage of reduction in area
3. Two specimens with the same dimensions and made from two different materials, A and B, were subjected to tensile testing. The percentage reduction in the area of the specimen made of material 'A' was calculated 3 times that of the specimen made of material B. In this case, O A lthe ductility of material A and B is equal O Bthe material A is brittle and material B is ductile O Cthe material B is more ductile than material A O D nhe material A is more ductile than material B 1. 20 O Aramak için buraya yazıin
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 158 kN. - Length of the specimen is 26 mm. The yield strength is 75 kN/mm2. - The percentage of elongation is 40 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 15 kN, iv) Young's Modulus if the elongation is 1 mm at 15 kN and (v) Final diameter if the percentage of reduction in area is 21 %. Solution Initial Cross-sectional Area (in mm-) The Diameter of the Specimen (in mm) Final Length of the Specimen (in mm) Stress at the elastic load (in N/mm-) Young's Modulus of the Specimen (in N/mm-) Final Area of the Specimen at Fracture (in mm)
Figure 1 shows the tensile testing results for different materials. All specimens have an initial diameter of 12 mm and an initial gauge length of 50 mm. 300 250 Low carbon steel Network polymer 200 Crystalline polymer 150 Amorphous polymer 100 50 5 10 15 20 25 30 Strain (%) Figure 1: Stress-strain curve b. Determine the following parameters for each material: • the tensile strength the 0.2% offset yield strength the modulus of elasticity • the ductility Stress (MPa) LO
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 152 kN. - Length of the specimen is 20 mm. - The yield strength is 86 kN/mm2. - The percentage of elongation is 48 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 10 kN, iv) Young's Modulus if the elongation is 2.2 mm at 10 kN and (v) Final diameter if the percentage of reduction in area is 28 %. Solution Initial Cross-sectional Area (in mm2) Answer for part 1 The Diameter of the Specimen (in mm) Answer for part 2 Final Length of the Specimen (in mm) Answer for part 3 Stress at the elastic load (in N/mm2) Answer for part 4 Young's Modulus of the Specimen (in N/mm2) Answer for part 5 Final Area of the Specimen at Fracture (in mm) Answer for part 6 Final Diameter of the Specimen after Fracture (in mm) Answer for part 7
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 159 kN. - Length of the specimen is 29 mm. - The yield strength is 82 kN/mm2. - The percentage of elongation is 47 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 19 kN, iv) Young's Modulus if the elongation is 2.8 mm at 19 kN and (v) Final diameter if the percentage of reduction in area is 21 %. Solution Initial Cross-sectional Area (in mm2) Answer for part 1 The Diameter of the Specimen (in mm) Answer for part 2 Final Length of the Specimen (in mm) Answer for part 3 Stress at the elastic load (in N/mm2) Answer for part 4 Young's Modulus of the Specimen (in N/mm2) Answer for part 5 Final Area of the Specimen at Fracture (in mm) Answer for part 6 Final Diameter of the Specimen after Fracture (in mm)
A 11 in. inner diameter, 0.35 " wall thickness pipe is under a pressure of 2.5 ksi where strain gages installed along axial and circumferential directions register strains of 180 and 900 micro-strains (x10^-6), respectively. A) What is the Poisson's Ratio of this material and it's Elastic Modulus? B) In a uniaxial test, the pipe's material is observed to yield at a longitudinal strain of 0.1 in/in. Assuming a factor of safety of 2, the pipe can withstand impact energy of _______ lb - in per foot without suffering permanent deformation. C) If the pipe is depressurized and then subjected to a torque of 50 lblb - ft.ft., it will experience a shear strain of ________ rad.