ubnetting IP Networks - Given the address block 192.168.30.0/24, create an IP addressing scheme that would allow for 2 subnets with 126 host IP addresses per subnet. Compute for the first two subnets only
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Subnetting IP Networks - Given the address block 192.168.30.0/24, create an IP addressing scheme that would allow for 2 subnets with 126 host IP addresses per subnet. Compute for the first two subnets only
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- • IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits4 LANS are connected to a router (R1) with each LAN compares of several hosts connected to a switch. Each LAN cotains the following number of hosts (end devices and the gateway interface), • LANI à 30 Hosts • LAN2 à 15 Hosts • LAN3 à 20 Hosts • LAN4 à 3 Hosts You have received the address space 200.16.1.0/24. Use the address space to create a subnetting scheme of four subnets with equal size in a way to accommodate the number of hosts required. Consider the following points in your answer, / Explain the procedure of your subnetting scheme / Highlight the suitable prefix and the subnet mask / Highlight the number of wasted hosts in each subnet after determining the most suitable prefix / Use the table below to provide the subnet details for each LAN Subnet Address First Host address Last Host address Broadcast address 1 LANI 2 LAN2 3 LAN3 4 LAN4Cisco Router A Network with id: 192.168.0.0 and subnet mask 255.255.0.0 is given to you to split it in such a way that the following classrooms are given adequate number of IPs based on their needs. Each classroom will occupy its own subnet. The following information for each subnet must be included: Subnet ID CIDR Subnet Mask First IP usable in the subnet Last IP usable in the subnet Broadcast IP Address for the subnet Classroom1: 8 PCsClassroom2: 400PC and 4 PrinterClassroom 3: 2 PCsClassroom4: 62 PCs and a ServerClassroom5: 24PCs
- 12 IKT204-G H21, IP and subnet Suppose an ISP owns the block of IPV4 addresses of the form 105. 16.80.0/23. Suppose it wants to create a total of five sub-nets (SN) from this block, by first dividing the address block into four sub-nets and then dividing the last sub-net into two so that the first three blocks have the same number of IP addresses and the last last two blocks have the same number of IP addresses. What are the prefixes (of the form a.b.c.d/x) for the five sub-nets in increasing order? SN1: 105. 16. SN2: 105. 16. SN3. 105 16. SN4: 105. 16. SN5. 105 16. How many bits constitutes the host portion of the prefixes created for SN1, SN2 and SN3? bits How many hosts may be assigned an IP address within SN4 and SN5? hosts44- An organization currently requires 40 hosts for its sales department. Given the IP Address 194.12.1.0 /24, design an optimal address scheme usingTradition Subnetting method, which will enable the connection of the sales department’s 40 hosts in one subnet and uses the remaining subnets for other departments’ hosts in the future. What will be the total number of usable (assignable) addresses per subnet? Select one: A. 62 B. 65 C. 63 D. 64SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hosts
- Design a classfull network addressing scheme that will supply the minimum number of hosts per subnet, and allow enough extra subnets and hosts for 25% growth in all areas. IP Address 172.16.0.0 FO/O S//0/1 FO/O Sales Administrative FO/1 185 Hosts 30 Hosts SO/0/0 Marketing 50 Hosts,q41- An organization currently requires 40 hosts for its sales department. Given the IP Address 194.12.1.0 /24, design an optimal address scheme usingTradition Subnetting method, which will enable the connection of the sales department’s 40 hosts in one subnet and uses the remaining subnets for other departments’ hosts in the future. Based on the designed address scheme, answer the question 41 – 50How many bits were borrowed for subnetting? Select one: A. 2 B. None of the above C. 4 D. 3Basic Subnetting - all subnets of EQUAL siaetets of EQUAL Q1: Given an IPV4 address 165.70.58.0/23, design and apply an IP addressing scheme for the topology shown in Figure 1. You must subnet to provide enough address space to use. Each LAN requires enough IP addresses to support at least 40 hosts. The point-to-point WAN links between two routers only require at least 2 host addresses. Complete the table below, Figure 1 Topology for Question Subnet # Subnet Address Address Range Broadcast Address Subnet Mask# of Wasted Host Network Prefix Addresses 1 3. 4
- Internet protocol version 6 (IPV6) has been introduced to replace the previous version (IPV4), Which of the following best describes a benefit of IPV6 over IPV4? A IPV6 addresses are shorter than IPV4 addresses, which allows for faster routing of packets. B IPV6 allows for a greater number of addresses than IPV4, which allows more devices to be connected to the Internet. IPV6 eliminates the use of hierarchy in addressing, making addresses easier to use. D IPV6 allows users to bypass older security protocols so that data can be sent peer-to-peer without the use of routers.Write a Java TCP Client-Server Program for Currency Converter as shown below. () CLIENT SERVER IP Address: 128.36.69.6 Domain Name. CurrencyConveret Port : 2834 NOTE Server Details are in the above figure > Client-Server communicates continuously until the Client send Bye to the Server NOTE: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Sample Output: Client From Server Present Currency Rates: 1 SAR = 0.26 USD (US Dollar) 1 SAR = 0.24 EUR (Euro) 1 SAR = 0.20 GBP (British Pound) 1 SAR = 1.73 CNY (Chines Yuan) Server Server Waiting for the Cline to be Connected... CONECTION ESTABLISHED Received From Client : 10 SAR Received From Client: BYE Enter currency in SAR or BYE to EXIT: 10 Received from Server : 10 SAR = 2.6 USD (US Dollar) 10 SAR = 2.4 EUR (Euro) 10 SAR = 2.0 GBP (British Pound) 10 SAR = 17.3 CNY (Chines Yuan) Enter currency in SAR : BYE Received from Server: Thank You For Using My Program Client DISCONNECTEDDesign a classfull network addressing scheme that will supply the minimum number of hosts per subnet, and allow enough extra subnets and hosts for 25% growth in all areas. IP Address 172.16.0.0 FO/0 S/0/1 FO/O Sales Administrative Router A FO/1 SO/0/0 185 Hosts 30 Hosts Marketing 50 Hosts