MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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## Problem: Mutually Exclusive Events

Given:
- Events \( U \) and \( V \) are mutually exclusive.
- \( P(U) = 0.26 \)
- \( P(V) = 0.37 \)

Find the following probabilities:

### a. \( P(U \cap V) \)

### b. \( P(U \cup V) \)

### c. \( P(U | V) \)

**Solution:**

**a. Finding \( P(U \cap V) \)**

Since \( U \) and \( V \) are mutually exclusive, their intersection is empty. Therefore, 
\[ P(U \cap V) = 0 \]

**b. Finding \( P(U \cup V) \)**

The Union of \( U \) and \( V \) for mutually exclusive events:
\[ P(U \cup V) = P(U) + P(V) \]
\[ P(U \cup V) = 0.26 + 0.37 \]
\[ P(U \cup V) = 0.63 \]

**c. Finding \( P(U | V) \)**

For mutually exclusive events, the conditional probability \( P(U | V) \) is given by:
\[ P(U | V) = \frac{P(U \cap V)}{P(V)} \]
Since \( P(U \cap V) = 0 \) (from part a),
\[ P(U | V) = \frac{0}{0.37} = 0 \]

So, the answers are:
- \( P(U \cap V) = 0 \)
- \( P(U \cup V) = 0.63 \)
- \( P(U | V) = 0 \)
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Transcribed Image Text:## Problem: Mutually Exclusive Events Given: - Events \( U \) and \( V \) are mutually exclusive. - \( P(U) = 0.26 \) - \( P(V) = 0.37 \) Find the following probabilities: ### a. \( P(U \cap V) \) ### b. \( P(U \cup V) \) ### c. \( P(U | V) \) **Solution:** **a. Finding \( P(U \cap V) \)** Since \( U \) and \( V \) are mutually exclusive, their intersection is empty. Therefore, \[ P(U \cap V) = 0 \] **b. Finding \( P(U \cup V) \)** The Union of \( U \) and \( V \) for mutually exclusive events: \[ P(U \cup V) = P(U) + P(V) \] \[ P(U \cup V) = 0.26 + 0.37 \] \[ P(U \cup V) = 0.63 \] **c. Finding \( P(U | V) \)** For mutually exclusive events, the conditional probability \( P(U | V) \) is given by: \[ P(U | V) = \frac{P(U \cap V)}{P(V)} \] Since \( P(U \cap V) = 0 \) (from part a), \[ P(U | V) = \frac{0}{0.37} = 0 \] So, the answers are: - \( P(U \cap V) = 0 \) - \( P(U \cup V) = 0.63 \) - \( P(U | V) = 0 \)
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