ty'' +(2t - 1)y' - 2y = 5t² e -2t. A general solution is y(t) = Y₁ = 2t - 1, Y₂=e-2t

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 3YT
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12 help use variation of parameters to finda general solution to the differntial equation given the function y1 and y2 are linearly independent solutions to the corresponding homogenous equation for t>0
ty"' + (2t - 1)y' - 2y = 5t² e -2t.
A general solution is y(t) =
Y₁ = 2t - 1,
Y₂=e-2t
Transcribed Image Text:ty"' + (2t - 1)y' - 2y = 5t² e -2t. A general solution is y(t) = Y₁ = 2t - 1, Y₂=e-2t
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