Two wattmeter's are connected to measure the input power of a balanced three phase load by two wattmeter method. If the wattmeter readings are W1 = 9800 W and W2= 3600 W and the reverse switch being operated on the meter indicating 3600 W, then the load power factor is given by,

In a 3-phase power measurement by two wattmeter method, both the wattmeter's shows identical readings. The power factor of the load is Select one: O a. Unity Ob.0.8 leading O C. Zero d. 0.8 lagging

26. In a two wattmeter method of power measurement of a balanced load,  wattmeter readings are -66.8 kW and  -16.8 kW. The reversing switch is operated in the first wattmeter showing -66.8 kW. find (a) total input power and (b) load power factor.

In the balanced three phase power measurement using two wattmeter method, each wattmeter reads 18 kW , when the pf is unity. What does each wattmeter reads when the pf falls to (i) 0.707 lag and (ii) 0.422 lag. The total three-phase power remains unchanged. (i) W1 at 0.707 lag (i) W2 at 0.707 lag (ii) W1 at 0.422 lag (ii) W2 at 0.422 lag

A single phase two wire a.c. Find the percentage saving in feeder copper if the system voltage is increased from 440 V to 1100 V. Assume same power is transmitted in both, same power loss and same power factor in both. I₁ I₁ 440V (a) 12 1100V 12 (b)

An alternator is connected in star. If the phase voltage is 110 V, the line voltage is *

In two wattmeter method of 3-phase power measurement, both meter reads positive when the phase angle is greater than 60° O zero O less than 60° equal to 60°