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two times incorrect includingp code.

two times incorrect includingp code.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Hi i got two times incorrect includingp code. 

 

1. FizzBuzz 2.0 by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, implement these conditions in the game: • print "Fizz" if the number is divisible by 3 • print "Buzz" if the number is divisible by 5 • print "FizzBuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met Input 1. An integer Output The first line will contain a message prompt to input the integer. The succeeding lines will contain either a string or an integer. Enter n: 15 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz main.c 9 10 11 12 =======2==***** 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 #include<stdio.h> main int n; printf("Enter n: "); scanf("%d,&n"); int n1 = 0; } while (n-c-n1):{ if (n%30 && n%5--0); { printf("fizzbuzz"); } else if("%3--0"); { printf("fizz"); } else if("%5--0"); { printf("buzz"); } } Test Cases Executions main.c:20:5: error: 'else' without a previous 14" 20 | else if("nXS--0"); I Expected Output Enter n: 15 1 2 FIZZ 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz Ⓒ Test Case 2 Ⓒ Test Case 3
Transcribed Image Text:1. FizzBuzz 2.0 by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, implement these conditions in the game: • print "Fizz" if the number is divisible by 3 • print "Buzz" if the number is divisible by 5 • print "FizzBuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met Input 1. An integer Output The first line will contain a message prompt to input the integer. The succeeding lines will contain either a string or an integer. Enter n: 15 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz main.c 9 10 11 12 =======2==***** 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 #include<stdio.h> main int n; printf("Enter n: "); scanf("%d,&n"); int n1 = 0; } while (n-c-n1):{ if (n%30 && n%5--0); { printf("fizzbuzz"); } else if("%3--0"); { printf("fizz"); } else if("%5--0"); { printf("buzz"); } } Test Cases Executions main.c:20:5: error: 'else' without a previous 14" 20 | else if("nXS--0"); I Expected Output Enter n: 15 1 2 FIZZ 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz Ⓒ Test Case 2 Ⓒ Test Case 3
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