Hi i got two times incorrect includingp code. 1. FizzBuzz 2.0by CodeChum AdminRemember the game of FizzBuzz from the lasttime? Well, I thought of some changes in thegame, and also with the help of loops as well.Firstly, you'll be asking for a random integerand then loop from 1 until that integer. Then,implement these conditions in the game:• print "Fizz" if the number is divisible by3• print "Buzz" if the number is divisible by5• print "FizzBuzz" if the number isdivisible by both 3 and 5• print the number itself if none of theabove conditions are metInput1. An integerOutputThe first line will contain a message prompt toinput the integer.The succeeding lines will contain either a stringor an integer.Enter n: 1512Fizz4BuzzFizz78FizzBuzzmain.c9101112=======2==*****13141516171819202122232425262728#includemainint n;printf("Enter n: ");scanf("%d,&n");int n1 = 0;}while (n-c-n1):{if (n%30 && n%5--0);{printf("fizzbuzz");}else if("%3--0");{printf("fizz");}else if("%5--0");{printf("buzz");}}Test CasesExecutionsmain.c:20:5: error: 'else' without a previous 14"20 | else if("nXS--0");IExpected OutputEnter n: 1512FIZZ4BuzzFizz78FizzBuzz11Fizz1314FizzBuzzⒸ Test Case 2Ⓒ Test Case 3

Here,Use a for loop to iterate from 1 to given number n and then check for each of the number in…

Answered: two times incorrect includingp code.

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two times incorrect includingp code.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Hi i got two times incorrect includingp code.

1. FizzBuzz 2.0
by CodeChum Admin
Remember the game of FizzBuzz from the last
time? Well, I thought of some changes in the
game, and also with the help of loops as well.
Firstly, you'll be asking for a random integer
and then loop from 1 until that integer. Then,
implement these conditions in the game:
• print "Fizz" if the number is divisible by
3
• print "Buzz" if the number is divisible by
5
• print "FizzBuzz" if the number is
divisible by both 3 and 5
• print the number itself if none of the
above conditions are met
Input
1. An integer
Output
The first line will contain a message prompt to
input the integer.
The succeeding lines will contain either a string
or an integer.
Enter n: 15
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
main.c
9
10
11
12
=======2==*****
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
#include<stdio.h>
main
int n;
printf("Enter n: ");
scanf("%d,&n");
int n1 = 0;
}
while (n-c-n1):{
if (n%30 && n%5--0);
{
printf("fizzbuzz");
}
else if("%3--0");
{
printf("fizz");
}
else if("%5--0");
{
printf("buzz");
}
}
Test Cases
Executions
main.c:20:5: error: 'else' without a previous 14"
20 | else if("nXS--0");
I
Expected Output
Enter n: 15
1
2
FIZZ
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
Ⓒ Test Case 2
Ⓒ Test Case 3

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