Two test charges are located in the ?x–?y plane. If ?1=−4.70 nCq1=−4.70 nC and is located at ?1=0.00 m,x1=0.00 m, ?1=0.680 m,y1=0.680 m, and the second test charge has magnitude of ?2=3.00 nCq2=3.00 nC and is located at ?2=1.20 m,x2=1.20 m, ?2=0.550 m,y2=0.550 m, calculate the ?x and ?y components, ?xEx and ?y,Ey, of the electric field ?⃗ E→ in component form at the origin, (0,0). The Coulomb force constant is 1/(4??0)=8.99×109 N·m2/ C2.
Two test charges are located in the ?x–?y plane. If ?1=−4.70 nCq1=−4.70 nC and is located at ?1=0.00 m,x1=0.00 m, ?1=0.680 m,y1=0.680 m, and the second test charge has magnitude of ?2=3.00 nCq2=3.00 nC and is located at ?2=1.20 m,x2=1.20 m, ?2=0.550 m,y2=0.550 m, calculate the ?x and ?y components, ?xEx and ?y,Ey, of the electric field ?⃗ E→ in component form at the origin, (0,0). The Coulomb force constant is 1/(4??0)=8.99×109 N·m2/ C2.
Related questions
Question
Two test charges are located in the ?x–?y plane. If ?1=−4.70 nCq1=−4.70 nC and is located at ?1=0.00 m,x1=0.00 m, ?1=0.680 m,y1=0.680 m, and the second test charge has magnitude of ?2=3.00 nCq2=3.00 nC and is located at ?2=1.20 m,x2=1.20 m, ?2=0.550 m,y2=0.550 m, calculate the ?x and ?y components, ?xEx and ?y,Ey, of the electric field ?⃗ E→ in component form at the origin, (0,0). The Coulomb force constant is 1/(4??0)=8.99×109 N·m2/ C2.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 6 steps with 6 images