Two tangents converge at an angle 27.4 degrees, which were connected by a reverse curve having common radius. The direction of the second tangent is due to East which is having a shortest distance to the first vertex of 163.04 meters. Station PC is at 10+615.2 and the bearing of the common tangent is S 44.3 E. Compute for the total cost of the curve from PC to PT in pesos. The following are the cost index and specification: Type of Pavement - Item 311 (Portland Cement Concrete Pavement) Number of Lanes-3 Lanes Width of Pavement - 4.0 m per lane Thickness of Pavement 15.1 cm Unit Cost - Php 1,585.93 per cubic meters

Consider the three level sections shown in Table 1. If the width of the road, b=12 m, calculate the slope of the side slopes of the sections.  If the combined volume of the given sections has been calculated using the Average End Area method and is given as 215813 m3, correct this volume using the prismoidal volume correction formula.

A temporary, 2 lane road is to be built connecting the 2 westbound lanes of Highway 1 near Tompkins, Saskatchewan with the parallel 2 eastbound lanes, 600 metres to the south (centreline to centreline). This temporary road is comprised of two equal circular, horizontal curves connected by a tangent section, which has a bearing of 045°. For the following data: radius of curvature=500m; maximum superelevation=0.04m/m; maximum side friction=0.12; lane width=3.70m. Find: i) the design speed of the curved sections and ii) the total length of the new pavement required

For a highway curve with Da = 5°00', I = 20°30', and Pl station = 63 +25.53 ft, calculate the requested values to lay out the circular curve at full stations (100 ft). Part A Calculate the radius. Express your answer to two decimal places and include appropriate units. R= Part B μA L = Value Calculate the circular curve length. Express your answer to two decimal places and include appropriate units. μA Units Value ? Units ?