Two tail test with t-calc = 1.831 and degrees of freedom = 48. p-value of the test is:   a) 0.05 < p-value < 0.1   b) 0.1 < p-value < 0.2   c) 0.01 < p-value < 0.02   d) 0.02 < p-value < 0.05

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 196.2 cm and a standard deviation of 1.9 cm. For shipment, 23 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 195 cm and 196 cm.P(195 cm < ¯x < 196 cm) = Enter your answer as a number accurate to 4 decimal places. Answers should be obtained using z-scores correct to two decimal places.

Solve for B)  I tried solving it which I got 12 minutes. Which it was wrong. I don't know what is the pro

A random sample of n, = 49 measurements from a population with population standard deviation o, = 3 had a sample mean of x, = 9. An independent random sample of n, = 64 measurements from a second population with population standard deviation o, = 4 had a sample mean of x, = 11. Test the claim that the population means are different. Use level of significance 0.01. (a) Check Requirements: What distribution does the sample test statistic follow? Explain. O The Student's t. We assume that both population distributions are approximately normal with known standard deviations. O The standard normal. We assume that both population distributions are approximately normal with known standard deviations. O The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. O The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations. (b) State the hypotheses. O Ho: H1 = H2; H;:H,…