Two steel guitar strings have the same length. String A has a diameter of 0.55 mm and is under 440.0 N of tension String B has a diameter of 1.1 mm and is under a tension of 840.0 N/You may want to review (Pages 461- 463) Part A Find the ratio of the wave speeds, VA/vB. in these two strings.

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uniform TEM plane wave propagating in a medium has H = -6 e- cos(2n x 10't - Bz) âg + 2e"sin (2m x 10't – Bz)â, A/m. If the medium is characterized by 4=20, e=1, o=3 S/m. a. Is the medium a good or a poor conductor? Determine a and B. b. What is the characteristic impedance, n? c. Determine the E field.

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 39.0 vibrations in 28.0 s. Also, a given maximum travels 425 cm along the rope in 15.0 s. What is the wavelength? cm Submit Answer

Part A Two steel guitar strings have the same length. String A has a diameter of 0.60 mm and is under 430.0 N of tension. String B has a diameter of 1.5 mm and is under a tension of 850.0 N . You may want to review (Pages 461 - 463) . Find the ratio of the wave speeds, vA/VB, in these two strings. Express your answer using two significant figures. Hνα ΑΣφ VA/VB = Submit Request Answer

The elastic limit of the gold forming a piece of wire is equal to 2.0 x 108 Pa. What is the maximum speed at which transverse wave pulses can propagate along this wire without exceeding this stress? (The density of gold is 1.93 x 104 kg/m³) m/s Submit Answer ASK YOUR TEACH F12 delete retu

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 44.0 vibrations in 29.0 s. Also, a given maximum travels 425 cm along the rope in 5.0 s. What is the wavelength? cm Need Help? Read It Watch It

Q18 An Ethernet cable is 3.85 m long. The cable has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the taut cable. The pulse makes four trips down and back along the cable in 0.715 s. What is the tension in the cable?

Part A Two steel guitar strings A and B have the same length and are under the same tension. String A has a diameter of 0.65 mm and string B has a diameter 1.17 mm. Treat the stretched-out strings as right cylinders with length L and radius r having volume n L. You may assume that both strings are made of the same material, so they have the same density. The ratio of the wave speeds, VA/VB, in the two strings is (enter your answer with two significant figures) possibly useful: density = mass/volume v = Af string fixed at both ends: An = 2L/n ; n = 1, 2, 3, 4, 5... %3D V = squareroot[F/µ) H = mass per unit length 1.8 Sumit Previous Answers Correct Part B The ratio of the eleventh harmonic frequency of string A to the eleventh harmonic frequency of string B, (111)A/(f11)B, is (enter your answer with two significant figures) 1.8 Bubm Previous Answers Correct