Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have 320 and 550 turns, respectively. A current of 3.00 A in solenoid A produces an average flux of 300 uWb through each turn of A and a flux of 90.0 uwb through each turn of B. (a) Calculate the mutual inductance of the two solenoids. mH (b) What is the inductance of A? mH (c) What is the magnitude of the emf that is induced in B when the current in A changes at the rate of 0.500 A/s? mv

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### Problem Statement

Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have **320** and **550** turns, respectively. A current of **3.00 A** in solenoid A produces an average flux of **300 μWb** through each turn of A and a flux of **90.0 μWb** through each turn of B.

1. **(a) Calculate the mutual inductance of the two solenoids.**

   \(\_\_\_\) mH

2. **(b) What is the inductance of A?**

   \(\_\_\_\) mH

3. **(c) What is the magnitude of the emf that is induced in B when the current in A changes at the rate of **0.500 A/s**?**

   \(\_\_\_\) mV

### Explanation

This exercise involves calculating mutual inductance, inductance, and electromotive force (emf) using the properties of coupled solenoids. 

1. **Mutual Inductance Calculation:**
   - Formula: \( M = N_B \times \Phi_B / I \)
   - Where \( N_B \) is the number of turns in solenoid B, \( \Phi_B \) is the magnetic flux through B, and \( I \) is the current in solenoid A.

2. **Inductance of Solenoid A:**
   - Formula: \( L_A = N_A \times \Phi_A / I \)
   - Where \( N_A \) is the number of turns in solenoid A and \( \Phi_A \) is the magnetic flux through A.

3. **Induced emf in B:**
   - Formula: \( \text{emf} = -M \times (dI/dt) \)
   - Where \( dI/dt \) is the rate of change of current in solenoid A.

This information would be valuable for anyone studying electromagnetic induction and the properties of solenoids in electrical circuits.
Transcribed Image Text:### Problem Statement Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have **320** and **550** turns, respectively. A current of **3.00 A** in solenoid A produces an average flux of **300 μWb** through each turn of A and a flux of **90.0 μWb** through each turn of B. 1. **(a) Calculate the mutual inductance of the two solenoids.** \(\_\_\_\) mH 2. **(b) What is the inductance of A?** \(\_\_\_\) mH 3. **(c) What is the magnitude of the emf that is induced in B when the current in A changes at the rate of **0.500 A/s**?** \(\_\_\_\) mV ### Explanation This exercise involves calculating mutual inductance, inductance, and electromotive force (emf) using the properties of coupled solenoids. 1. **Mutual Inductance Calculation:** - Formula: \( M = N_B \times \Phi_B / I \) - Where \( N_B \) is the number of turns in solenoid B, \( \Phi_B \) is the magnetic flux through B, and \( I \) is the current in solenoid A. 2. **Inductance of Solenoid A:** - Formula: \( L_A = N_A \times \Phi_A / I \) - Where \( N_A \) is the number of turns in solenoid A and \( \Phi_A \) is the magnetic flux through A. 3. **Induced emf in B:** - Formula: \( \text{emf} = -M \times (dI/dt) \) - Where \( dI/dt \) is the rate of change of current in solenoid A. This information would be valuable for anyone studying electromagnetic induction and the properties of solenoids in electrical circuits.
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