Two sinusoidal waves of wavelength A= 2/3 m and amplitude A = 6 cm anddiffering with their phase constant, are travelling to the right with same velocity v= 50 m/s. The resultant wave function y res (xt) will have the form:O y_res (x t) - 12(cm) cos(p/2) sin(3x-150nt=p/2).O y res (xt) -12(cm) cos(o/2) sin(3x150T-0/2),O y res (xt) 12(cm) cos(p/2) sin(150rtx-3Tt-0/2).O y res (x,t) 12(cm) cos(o/2) sin(3x-180nt-0/2)O y res (x,t) =12(cm) cos(o/2) sin(150nx-3rt-0/2),

Standing waves are formed by the superposition of two travelling waves of the same frequency (with…

Two sinusoidal waves of wavelength À = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y res (x.t) will have the form:

Two sinusoidal waves of wavelength À = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y res (x.t) will have the form:

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter16: Waves

Section: Chapter Questions

Problem 93P: Two sinusoidal waves are moving through a medium in the same direction, both having amplitudes of...

See similar textbooks

Similar questions

Consider a sound wave moving through the air modeled with the equation s(x,t)=6.00nmcos(54.93m1x18.84103s1t) . What is the shortest time required for an air molecule to move between 3.00 nm and -3.00 nm?
Two sinusoidal waves are moving through a medium in the same direction, both having amplitudes of 3.00 cm, a wavelength of 5.20 m, and a period of 6.52 s, but one has a phase shift of an angle . What is the phase shift if the resultant wave has an amplitude of 5.00 cm? [Hint: Use the trig identity sinu+sinv=2sin(u+v2)cos(uv2)
Two sinusoidal waves of wavelength A = 2/3 m and amplitude A = 6 cm and %3D differing with their phase constant, are travelling to the right with same velocity v = 60 m/s. The resultant wave function y res (x,t) will have the form: %3D O y_res (x,t) = 12(cm) cos(p/2) sin(150rtx-3rt+p/2). %3D O y-res (x,t) = 12(cm) cos(4/2) sin(3tx-150rt+p/2). %3D O y_res (x,t) = 12(cm) cos(4/2) sin(150tx+3rt+p/2). %3D O y_res (x,t) = 12(cm) cos(p/2) sin(3rtx+150rt+p/2). %3D O y-res (x,t) = 12(cm) cos(4/2) sin(3rtx-180rt+p/2). %3D A standing wave on a string of length L = 3 m is described by the following
300 Hz O 75 Hz Two sinusoidal waves of wavelength À = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y res (x,t) will have the form: O y res (x,t) = 12(cm) cos(p/2) sin(3nx-180nt+p/2). O y res (x,t) = 12(cm) cos(@/2) sin(150tx+3rt+p/2). O y res (x,t) - 12(cm) cos(p/2) sin(150nx-3rt+p/2). %3D O y res (x,t) = 12(cm) cos(p/2) sin(3nx+150rt+p/2). O y res (x,t) = 12(cm) cos(@/2) sin(311x-150nt+p/2). %3D
Two sinusoidal waves of wavelength A = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y_res (x,t) will have the form: O y-res (x,t) = 12(cm) cos(p/2) sin(150tx-3rtt+p/2). O y_res (x,t) = 12(cm) cos(p/2) sin(3Tx-150t+4/2). O y_res (x,t) = 12(cm) cos(p/2) sin(3Ttx-180rtt+p/2). O y-res (x,t) = 12(cm) cos(p/2) sin(150rtx+3rt+p/2). O y_res (x,t) = 12(cm) cos(p/2) sin(3Ttx+150rtt+p/2).
50 Hz Two sinusoidal waves of wavelength A = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the left with same velocity v = 50 m/s. The resultant wave function y_res (x,t) will have the form: y_res (x,t) = 12(cm) cos(p/2) sin(3TIX+150rtt+p/2). %3D O y-res (x,t) = 12(cm) cos(p/2) sin(150Ttx+3Tt+p/2). O y-res (x,t) = 12(cm) cos(p/2) sin(3TTX-150rt+p/2). O y-res (x,t) = 12(cm) cos(4/2) sin(150rx-3nt+p/2). O y res (x,t) = 12(cm) cos(p/2) sin(3TX-180rtt+o/2). Clear selection
y2 = 0.01 sin(5rx+40rt), O y1 = 0.04 sin(20x-320nt); y2 = 0.04 sin(20TDX-+320rt), Two sinusoidal waves of wavelengthA = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y_res (x,t) will have the form: O y res (x,t) = 12(cm) cos(p/2) sin(3ttx+150rtt+p/2). O y_res (x,t) = 12(cm) cos(p/2) sin(3nx-180nt+p/2). y_res (x,t) = 12(cm) cos(p/2) sin(3nx-150nt+p/2). O y res (x,t) = 12(cm) cos(p/2) sin(150rtx-3nt+p/2). y_res (x,t) = 12(cm) cos(@/2) sin(150tx+3nt+p/2). Two identical sinusoidal waves with wavelengths of 1.5 m travel in the same. direction at a speed of 10 m/s. If the two waves originate from the same starting
docs.google.com/forms/d/e/1Ff o Two sinusoidal waves of wavelength A = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v = 50 m/s. The resultant wave function y_res (x,t) will have the form: y_res (x,t) = 12(cm) cos(4/2) sin(3Tx+150rt+p/2). y_res (x,t) = 12(cm) cos(4/2) sin(150Ttx+3nt+p/2). y_res (x,t) = 12(cm) cos(4/2) sin(150ttx- 3nt+p/2). y_res (x,t) = 12(cm) cos(4/2) sin(3tx- 150rtt+p/2). y_res (x,t) = 12(cm) cos(p/2) sin(3tx- 180nt+p/2). العربية الإنجليزية ... +
Two sinusoidal waves of wavelength A = 2/3 m and amplitude A = 6 cm and differing with their phase constant, are travelling to the right with same velocity v 50 m/s. The resultant wave function y res (x,t) will have the form:
6:18 Consider a composite wave formed by two plane waves with slightly different frequencies of 0 = 2.7 x 10" rad/s and o, = 2.9 x 10' rad/s and respective wavelengths A = 17.0 nm and A, = 16.0 nm. Calculate the propagation velocity of the carrier wave and give your results in units of m/s with 1 digit precision, rounding off to one decimal place, i.e. the nearest tenth. (time budget 5min)
Consider a composite wave formed by two plane waves with slightly different frequencies of 0, = 2.7 x 1012 rad/s and aw2 = 2.9 × 1012 rad/s and respective wavelengths A1 = 17.0 nm and 2 16.0 nm. Calculate the propagation velocity %D of the envelope wave and give your results in units of m/s with 1 digit precision, rounding off to one decimal place, i.e. the nearest tenth. (time budget 5min)
Two transverse sinusoidal waves combining in a string are described by the wave functions y1 = 0.02 sin(4Ttx+rtt) and y2 = 0.02 sin(4Ttx-Ttt), where x and y are in meters, andt is in seconds. If after superposition, a standing wave of 3 loops is formed, then the length of the string is: O 2 m 1.5 m 0.5 m 0.75 m