Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Two proteins bind to the same ligand with the following Kd's.
Protein 1: 10 μΜ
Protein 2: 100 nM
Which protein would be bound to more ligand at a ligand concentration of 10 μM? (Assume a limiting concentration of each protein)
Expert Solution
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Dissociation concentration
Consider the following reaction:
P + L PL
where P is the protein, L is the ligand and k1 and k2 are rate constants.
Ka is the equilibrium constant also known as the Association Constant
Ka = k1/k2 = [PL] / [P] [L] ...EQ1
The reciprocal of the association constant is Dissociation Constant, denoted by Kd
Kd = 1/Ka
= [P] [L] / [PL]
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