Answered: Two positive point charges q1=4.40 uC…

Two positive point charges q1=4.40 uC and q2=6.40 uC are separated in vaccum in distacne of 6.0m find the magnitude of the net electric at point r!=4.80m from q1 in N/C

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...

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Concept explainers

Types of Charge Carriers

A carrier is a type of object which carries a particular thing from one point to another point. For instance, people use different vehicles from one place to another, and the vehicle carries those people and acts as a carrier.

Question

Two positive point charges q1=4.40 uC and q2=6.40 uC are separated in vaccum in distacne of 6.0m find the magnitude of the net electric at point r!=4.80m from q1 in N/C

Expert Solution

Step 1

Given data is -

$\begin{array}{rcl} Charge q_{1} & = & 4.4 μc \\ q_{2} & = & 6.40 μc \\ Distance & = & 6.0 m \\ Point r & = & 4.80 m \\ Electric field E & = & k \frac{q}{r^{2}} \end{array}$

Step 2

So electric field due to $q_{1}$ .

$\begin{array}{rcl} r & = & \sqrt{{(6)}^{2} + {(4.80)}^{2}} \\ r & = & \sqrt{59.04} \\ r & = & 7.6 m \\ E_{1} & = & k \frac{q_{1}}{r^{2}} \\ k & = & 9 \times 10^{9} {Nm}^{2} / C = constant \\ E_{1} & = & \frac{8.99 \times 10^{9} \times 4.4 \times 10^{- 6}}{{(7.6)}^{2}} \\ E_{1} & = & 684.83 N/C \end{array}$

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