College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Two point charges are placed on the x axis. (Figure 1)The first charge, q1q1 = 8.00 nCnC , is placed a distance 16.0 mmfrom the origin along the positive x axis; the second charge, q2q2 = 6.00 nCnC , is placed a distance 9.00 mm from the origin along the negative x axis.
Calculate the electric field at point A, located at coordinates (0 mm, 12.0 mm ).
Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures.
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- the diagram as shown. The charges of each marble are q₁6.50 μC, 9₂ 1.17 pc, and q3 -1.79 μC. Marble q, is a distance r = 3.00 cm to the left of the marble q₂, while marble q, is a distance r3 - 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance = 1.00 cm to the left of the center marble. N/C 4 observation point 92 r₂ = 0m Another marble is placed 1 cm to the left of the middleimarble. If this new marble has a charge of 3.71 µC, calculate magnitude and direction of the force on it. 77. x magnitudearrow_forwardThree charges are placed along the x-axis: q1 = 3.00 µC at X1 = -20.0 cm, q2 = -5.00 µC at x2 = 10.0 cm, and q3 = 6.00 µC at x3 = 25.00 cm. Determine the magnitude of the electric field at the origin. O 4 69x106 N/C O 2 96x106 N/C O 6 04x106 N/C O 4.31x106 N/Carrow_forwardThere are two point charges q1=(7.000x10^0) µC and q2=(-3.0000x10^0) µC. q1 is located at origin (0, 0). q2 is located at (4.00x10^0) m,(5.000x10^0) m). Now we place another point charge q3 = (1.0000x10^1) µC at ((4.00x10^0) m, 0), i.e. q3 is right underneath of q2. Please calculated the X-component of the electrostatic force on q3 . Give your answer in the unit of N with 3 sf. Note: Use the sign to represent the direction, for example -2.11x10^-4 means the force is on the negative x direction.arrow_forward
- Two charges are located in the x-y plane. If q1 -3.50 nC and is located at (x = 0.00 m, y = 0.960 m), and the second charge has magnitude of q2 = 4.80 nC and is located at (x = 1.40 m, y 0.650 m), calculate the x and y components, Ex and Ey, of the electric field, É, in component form at the origin, (0, 0). The Coulomb force constant is 1/ (4reo) = 8.99 x 10° N · m²/C². -13.58 -40.45 Ex N/C Ey N/C Incorrect Incorrect IIarrow_forwardProblem 6: A positive charge of magnitude Q; = 0.45 nC is located at the origin. A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 12 cm from the origin. The point Pis located y = 18 cm above charge Q2. y R Q2 X ©theexpertta.com Part (a) Calculate the x-component of the electric field at point P due to charge Qj. Write your answer in units of N/C. Ex 1 =arrow_forwardConsider the symmetrically arranged charges in the figure, in which qa 9b = -2.45 µC and q. = qd = +2.45 µC. Determine the direction of the electric field at the location of charge q. O right up and left down and left up and right dn down left down and right Calculate the magnitude of the electric field E at the location of q given that the square is 6.35 cm on a side.arrow_forward
- The electric field in an xy plane produced by a positively charged particle is 6.20(6.61 + 6.3) N/C at the point (4.1, 4.6) cm and 123 N/C at the point (3.8, 0) cm. What are the (a) x and (b) y coordinates of the particle? (c) What is the charge of the particle? (a) Number i Unitsarrow_forwardPoints A, B, and C are at the vertices of an equilateral triangle. A certain positive charge q placed at A produces an electric field of magnitude 623 N/C at C. Suppose a second, identical charge is placed at B. What is the magnitude of the new electric field at C?arrow_forward
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