* Two narrow slits are used to produce a double-slit interfer- ence pattern 0.90 mm, and the interference pattern is projected onto a screen 9.5 m away from the slits. The central bright fringe is at a certain spot on the screen. Using a ruler with one end placed at the cen- tral fringe, you move along the ruler passing by two more bright fringes and find that the third bright fringe is 20 mm away che central fringe. What is the wavelength of the light? with monochromatic light. The slits are separated by from

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter37: Wave Optics
Section: Chapter Questions
Problem 37.3OQ: Suppose Youngs double-slit experiment is performed in air using red light and then the apparatus is...
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Question #30. Please use the attached equation sheet and start with an equation from the sheet and work from there. You can manipulate anyway you want you just have to start from the equation sheet.
30. * Two narrow slits are used to produce a double-slit interfer-
ence pattern with monochromatic light. The slits are separated by
0.90 mm, and the interference pattern is projected onto a screen
9.5 m away from the slits. The central bright fringe is at a certain
spot on the screen. Using a ruler with one end placed at the cen-
tral fringe, you move along the ruler passing by two more bright
fringes and find that the third bright fringe is 20 mm away
the central fringe. What is the wavelength of the light?
from
21
Transcribed Image Text:30. * Two narrow slits are used to produce a double-slit interfer- ence pattern with monochromatic light. The slits are separated by 0.90 mm, and the interference pattern is projected onto a screen 9.5 m away from the slits. The central bright fringe is at a certain spot on the screen. Using a ruler with one end placed at the cen- tral fringe, you move along the ruler passing by two more bright fringes and find that the third bright fringe is 20 mm away the central fringe. What is the wavelength of the light? from 21
MusH start w/one of These equahons
V-3.0 X10 ps Air light:
Use "v" for volume i no "L" use subscripts
Physics 104 Equation Sheet
Ho = 4n x 107 N/A?
c = 3.00 x 10% m/s
e = 1.6 x 10 19 C
Eo = 8.85 x 10 12 C²/Nm²
k = 9.0 x 10° Nm2/C²
h = 6.63 x 10 34 Js = 4.14 x 1015 eVs lo = 1012 w/m2
me = 9.11 x 10 31 kg
m, = 1.67 x 10 27 kg
nwater = 1.33
1 eV = 1.6 x 1019 J
nair = 1.00
nsoap = 1.50
Vsound = 340 m/s
Wsilver = 4.74 eV
AV = -EAx
PE = kqı92/r
V = kQ/r
F = kqıq2/r?
E = kQ/r?
F = qE
C = q/AV
APEE = -WE = -qEd
APE = qAV
PE = ½ QAV
C = E0A/d
ReqΣ R
1/ Req Σ 1/R
P = IAV
AV = IR
R = pL/A
F = ILB sino
F = qvB sino
EMF = NA DB/At
B = Hol/2nr
B = Honl
Os = BA cosO
IV1 = 12 V2
V1/V2 = N1/N2
EMF = NBAW sin(wt)
Frequencey.
W = 2nf =
f = 1/T
F = -kAx
V = fA
n = c/v
An = Aair/n
m
PE = ½ kAx?
V =
fs
ni sino1 = n2 sinO2 relachiorine o
1/o + 1/i = 1/f
fo =
fo = fs(1 ± °o/p)
d sino = mA
B = 10 log10 (1/lo)
2/l1 = r?/r,?
d sino = (m + ½ )A
m = -i/o
f = R/2
P = 1/f
E = hf
Am T = 2.90 x 10 mK
KEmax = hf – W
Rn = (0.0529 nm) n²
A = h/mv = h/p
A-N = (h/mc)(1 – cosO)
En = -13.6eV/n?
L = nh/2n
AxAp, 2 h/47
ΔΕΔt h/4π
Fomg sing
Transcribed Image Text:MusH start w/one of These equahons V-3.0 X10 ps Air light: Use "v" for volume i no "L" use subscripts Physics 104 Equation Sheet Ho = 4n x 107 N/A? c = 3.00 x 10% m/s e = 1.6 x 10 19 C Eo = 8.85 x 10 12 C²/Nm² k = 9.0 x 10° Nm2/C² h = 6.63 x 10 34 Js = 4.14 x 1015 eVs lo = 1012 w/m2 me = 9.11 x 10 31 kg m, = 1.67 x 10 27 kg nwater = 1.33 1 eV = 1.6 x 1019 J nair = 1.00 nsoap = 1.50 Vsound = 340 m/s Wsilver = 4.74 eV AV = -EAx PE = kqı92/r V = kQ/r F = kqıq2/r? E = kQ/r? F = qE C = q/AV APEE = -WE = -qEd APE = qAV PE = ½ QAV C = E0A/d ReqΣ R 1/ Req Σ 1/R P = IAV AV = IR R = pL/A F = ILB sino F = qvB sino EMF = NA DB/At B = Hol/2nr B = Honl Os = BA cosO IV1 = 12 V2 V1/V2 = N1/N2 EMF = NBAW sin(wt) Frequencey. W = 2nf = f = 1/T F = -kAx V = fA n = c/v An = Aair/n m PE = ½ kAx? V = fs ni sino1 = n2 sinO2 relachiorine o 1/o + 1/i = 1/f fo = fo = fs(1 ± °o/p) d sino = mA B = 10 log10 (1/lo) 2/l1 = r?/r,? d sino = (m + ½ )A m = -i/o f = R/2 P = 1/f E = hf Am T = 2.90 x 10 mK KEmax = hf – W Rn = (0.0529 nm) n² A = h/mv = h/p A-N = (h/mc)(1 – cosO) En = -13.6eV/n? L = nh/2n AxAp, 2 h/47 ΔΕΔt h/4π Fomg sing
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