Two masses on two slopes are connected with a massless rope through a frictionless pulley as below. Since the pulley is frictionless, the tension in the rope is the same on both sides. The 50 kg mass is on a frictionless surface. The 100 kg mass is on a surface with kinetic and static friction coefficient of 0.3. 100 kg 50 kg \ 30.0° 53.1° a. In what direction would the blocks move? Show work! b. What is the tension in the rope between the two masses? c. If the blocks moved to the left to begin with at 1 m/s, what would their speed and direction of motion be after 3 s?

A pile driver lifts a 250 kgkg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground. A fall of 1.5 mm before striking the pipe drives the pipe in 40 cmcm.     Part A What is the average force that the weight exerts on the pipe? (Hint: Let the weight be the system)

A 1,040-N crate is being pushed across a level floor at a constant speed by a force  F  of 390 N at an angle of 20.0° below the horizontal, as shown in the figure a below. Two figures show a side view of a crate positioned upon a horizontal surface. Figure (a): An arrow pointing downward and to the right is labeled vector F and forms an angle of 20° below the horizontal as it approaches the upper left edge of the crate. Figure (b): An arrow pointing upward and to the right is labeled vector F and forms an angle of 20° above the horizontal as it extends from the upper right edge of the crate. (a) What is the coefficient of kinetic friction between the crate and the floor? (Enter your answer to at least three decimal places.)(b) If the 390-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in the figure b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a).

A force in the +z-direction with magnitude 18.0 N- (0.530 N/m)z is applied to a 6.60 kg box F(x) that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. O Part A If the box is initially at rest at r = 0, what is its speed after it has traveled 16.0 m ? Express your answer to three significant figures and include the appropriate units. ? HA Value Units Submit Previous Answers Request Answer

Problem 7.36 The block of mass M in the following figure slides on a frictionless surface. (Figure 1) Part A Find an expression for the tension in the string. Express your answer in terms of the variables m, M, and appropriate constants. Hνα ΑΣφ ? T = Submit Request Answer Provide Feedback Figure Massless string M Massless, fric- tionless pulley m

A 1490 N crate is resting on a table connected to a 400 N block through a frictionless pulley system as shown.  Friction between the crate and the table is enough to keep the system at rest.  The arrows show the forces that act on the crate and the block.

com/course.html?courseld-17255520&OpenVellumHMAC=197f22d4a42226c194d42c759b32e18a#10001 Part A What is the speed of the potato at the lowest point of its motion? A 0.280 kg potato is tied to a string with length 1.50 m, and the other end of the string is tied to a rigid support. The potato is held straight out horizontally from the point of support, with the string pulled taut, and is then released. Express your answer in meters per second. [VD ΑΣΦ 49 a x Xb b √x x x x 1X1 V = m/s Submit Previous Answers Request Answer X Incorrect; Try Again Part B What is the tension in the string at this point? Express your answer in newtons. T = 8.23 N P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions Contact 12,772 APR ⠀⠀⠀ 28 A tv A O DII F8 2 M #3 E 80 F3 $ 4 000 000 F4 R % 5 F5 T A 6 F6 Y & 7 ◄◄ F7 U * 00 8 9 DD F9 0 ? X.10n X S ) 0 79 F10 P

Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use! If your building is on fire, simply reach out and grab the cord on the Oyoy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 106.0 kg and is shaped like a cylinder of radius R = 0.835 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0830 meters. The cord is wound around the small shaft and this is the secret to your low velocity. Outer Radius = R Spindle Radius = r Mass = M The FORMULA for the moment of Inertia: I = V(y=0)=? We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 77.5 kg is using the Oyoy and…

For the system shown, the coefficient of kinetic friction is 0.4 and the masses are 1 Kg each. If the system is Released from rest, determine the tension in the cord. B A

A hook A is at (1 m, -2 m, 2 m). A force ?⃑ = {−6?̂+ 9?̂+ 3? } ? is exerted on the hook. Deterine the angle between the force and the position vector ?⃑??, where O is the origin of thecoordinate system. Show the diagram.