Two identical bosons of mass m are placed in a one-dimensional potential 1 v(x)=mo'x². The bosons interact via a weak potential, V(* 2 V12 = V, expl- m2(x; -x,}° /4h %3D where and X2 denote coordinates of the particles. Given that the ground state 1 mox? wavefunction of the harmonic oscillator is y (x)=| 2h e The ground state energy of the two-boson system, to the first order in V,, is

icon
Related questions
Question
Two identical bosons of mass m
are placed in a one-dimensional potential
1
V(2
2
v(x)=mo'x². The bosons interact via a weak potential,
Vị2 = V, expl-m(x; -x,)° /4h|
%3D
where
and
X2
denote coordinates of the particles. Given that the ground state
1
mox?
то )4
wavefunction of the harmonic oscillator is y (x) =|
The ground state
2h
energy of the two-boson system, to the first order in V,,
is
Transcribed Image Text:Two identical bosons of mass m are placed in a one-dimensional potential 1 V(2 2 v(x)=mo'x². The bosons interact via a weak potential, Vị2 = V, expl-m(x; -x,)° /4h| %3D where and X2 denote coordinates of the particles. Given that the ground state 1 mox? то )4 wavefunction of the harmonic oscillator is y (x) =| The ground state 2h energy of the two-boson system, to the first order in V,, is
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer