Two forces, (71.0N in the positive x direction and 33 N in the negative y direction) act on a 156.0 kg object. Determine the magnitude of it's acceleration.

Three forces acting on an object are given by F₁ = (−2.2î + 6.85ĵ) N, F₂ = (4.75î – 1.25ĵ) N, and F3 = (-401) N. The object experiences an acceleration of magnitude 3.80 m/s². (a) What is the direction of the acceleration? 98.50 X Note that the direction of the acceleration is the same as the direction of the net force.° (counterclockwise from the +x-axis) (b) What is the mass of the object? 9.964 kg (c) If the object is initially at rest, what is its speed after 11.0 s? 41.8 m/s (d) What are the velocity components of the object after 11.0 s? (Let the velocity be denoted by v.) ✓ = -41.34 m/s +6.18

Two known forces, F1=2.95 N at 78 degrees above the x-axis and F2=3.55N at 39 degrees below the x-axis are acting upon an object. What is the magnitude of the third force, F3, so that the acceleration of the object is 0?

Two forces, F = 2.50 i N and F2 = (1.20 i – 2.30 j) N , act on a 3.00 kg object. Find the magnitude of acceleration of the object. a = 4.0V m/s?