Two forces,  1 = (3.75î − 5.25ĵ) N  and  2 = (2.35î − 7.65ĵ) N,  act on a particle of mass 2.10 kg that is initially at rest at coordinates  (+1.80 m, +4.10 m). (a) What are the components of the particle's velocity at t = 11.5 s? =         m/s(b) In what direction is the particle moving at t = 11.5 s? ° counterclockwise from the +x-axis(c) What displacement does the particle undergo during the first 11.5 s?Δ =         m(d) What are the coordinates of the particle at t = 11.5 s? x =  m y =  m

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”