College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A test charge of +2µC is placed halfway between a charge of +6µC and another of +4μC separated by distance 2d = 11 cm. +4uC 9₁ = +4 μC The free body diagram of q2 from Part 1 should look like this: +2μC F3-2 d N q2 = +2 μC F1-2 F3→2 > F1→2 +6μС The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. (b) Calculate the force on the test charge by the +4μC charge. N (c) Calculate the net force on the test charge by both the charges. X 93 = +6 μC because 93 > 91. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. Narrow_forwardTthree point charges, Q1 = 18.4 µC, Q2 -33.6 μC, and Q3 = 87.3 μC are positioned at three corners of a square as shown in the figure. A fourth point charge is located at the open corner at point A with a charge of QA = 15.5 μC. The square has height y of 40.1 cm and width x of 40.1 cm. Q, + Calculate the magnitude F of the net force on the charge at point A. 71.1 F = Incorrect y x A + Q3 Narrow_forwardThere are two point charges q1=(7.000x10^0) µC and q2=(-3.0000x10^0) µC. q1 is located at origin (0, 0). q2 is located at (4.00x10^0) m,(5.000x10^0) m). Now we place another point charge q3 = (1.0000x10^1) µC at ((4.00x10^0) m, 0), i.e. q3 is right underneath of q2. Please calculated the X-component of the electrostatic force on q3 . Give your answer in the unit of N with 3 sf. Note: Use the sign to represent the direction, for example -2.11x10^-4 means the force is on the negative x direction.arrow_forward
- A solution contains 5.62E11 Cl– ions and 1.35E11 Ca2+ ions. What is the total net charge in the solution (in Coulombs)?arrow_forwardThree point charges are fixed as shown in (Figure 1). Take q₁ = 20 μC, q2 = -30 μC, 93 = 40 μC, and d = 9.0 mm. The point charge of 3.6 μC is placed at the center of the triangle. Figure y Ke X 93 9₁ d ( d 1 of 1 92 > ▼ Part A What is the magnitude of the force exerted on the charge at the center of the triangle? Express your answer with the appropriate units. |F|net = Submit Part B I 0 = 346 μА O Value X Incorrect; Try Again; 5 attempts remaining N Previous Answers Request Answer What is the direction of the force exerted on the charge at the center of the triangle? Express your answer in degrees, measured counterclockwise from the positive x-axis. ?arrow_forwardThree charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q = 6.30 µC, 92 = 1.93 pC, and 93 = -2.20 pC. Marble q, is a distance r = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distancer = 1.00 cm to the left of the center marble. N/C observation point Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of -3.60 pC, calculate magnitude and direction of the force on it. magnitude direction -Select varrow_forward
- In the diagram below, A, B, and C are conducting spheres that are fixed in place and can be considered to be point charges. The spheres are fixed in place and each have a mass of 3.0 grams. Sphere A has a charge of +12µC, Sphere B has a charge of –9.0µC, and Sphere C has a charge of –6.0µC. Spheres A and B are separated by a distance of 0.020 m and Spheres B and C are separated by a distance of 0.010 m. 0.020 m 0.010 m A B C +12 μC -9 μC -6 μC What is the magnitude of the net force (in Newtons) acting on Sphere B? Write your answer as a number only. Do not include units in your answer.arrow_forwardProblem 4: Charge Q1 = 2.8 µC is located at r = (3.4i – 2.0j + 4.5k) m. A second charge Q, = 3.9 µC is located at r, = (8.0i – 3.6j – 9.0k) m. Part (a) What is the magnitude of the force of the second charge on the first charge in newtons? Numeric :A numeric value is expected and not an expression. Part (b) The force of the second charge on the first charge can be written using unit vectors as follows: F= Fi+F,j+F,k What is the value of F, in newtons? Numeric :A numeric value is expected and not an expression. Part (c) What is the value of F, in newtons? Numeric :A numeric value is expected and not an expression. Fy- Part (d) What is the value of F, in newtons? Numeric :A numeric value is expected and not an expression.arrow_forwardA conducting sphere of radius r1 = 0.46 m has a total charge of Q = 2.9 μC. A second uncharged conducting sphere of radius r2 = 0.23 m is then connected to the first by a thin conducting wire. The spheres are separated by a very large distance compared to their size. r1 = 0.46 mr2 = 0.23 mQ = 2.9 μC What is the total charge on sphere two, Q2 in coulombs?arrow_forward
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