Two charges are fixed on the x axis: one with a charge of q1 = 5.00 μC at x1 = -1.00 m and the other with a charge of q2 = 3.00 μC at x2 = 1.50 m . Find the force F exerted on a charge q = -5.00 μC placed at the origin (x=0). Which of the following gives the proper directions for the forces on charge q due to charges q1 and q2? F1 is the force on charge q due to charge q1, and F2 is the force on charge q due to charge q2. Standard coordinates are being used (i.e., "left" is the negative x direction, and "right" is the positive x direction).

Two charged particles are a distance of 1.92 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.10 nC. (a) What is the magnitude (in N) of the electric force that one particle exerts on the other? N (b) Is the force attractive or repulsive? O attractive O repulsive

A charge 4.98 nC is placed at the origin of an xy-coordinate system, and a charge -2.02 nC is placed on the positive x-axis at x = 4.02 cm . A third particle, of charge 6.02 nC is now placed at the point x = 4.02 cm , y = 3.04 cm . Find the x-component of the total force exerted on the third charge by the other two.   Find the y-component of the total force exerted on the third charge by the other two.   Find the magnitude of the total force acting on the third charge.     Find the direction of the total force acting on the third charge.

Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q = 5.28 nC at the origin. (Let r12 = 0.240 m.) Three point charges lie along the axes in the x y-coordinate plane. Positive charge q is at the origin. A charge of 6.00 nC is at (r1 2, 0), where r1 2 > 0. A charge of −3.00 nC is at (0, −0.100 m). magnitude      N direction      ° counterclockwise from the +x-axis

Three charges are arranged as shown below: 9₁ = 22 µC is at the origin, q2 = -10 µC is at a distance of b = 0.55 m along the vertical axis, and q3 = 16 µC is at a distance of a 0.4 m along the horizontal axis. Find the forces exerted on 9₁ by 92, by 93 and by 92 and q3 together (the net force). = b 92 91 a 93 = The magnitude of the force on q₁ due 92, F12: The direction of the force on q₁ due q2 is Select an answer The magnitude of the force on 9₁ due 93, F13 = The direction of the force on 9₁ due q3 is Select an answer ✓ The magnitude of the net force on 9₁, F1, Net The direction of the net force on q₁ is Select an answer ✓ Units Select an answer ✓ Units Select an answer ✓ Units Select an answer ✓

Particle A of charge 3.09 *10-4 C is at the origin, particle B of charge -5.40 *10-4 C is at (4.00 m, 0), and particle C of charge 1.01 *10-4 C is at (0, 3.00 m). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C?

Particle A of charge 3.00 x 10-4 C is at the origin, particle B of charge -6.00 x 10-4 C is at (4.00 m, 0), and particle C of charge 1.00 x 10-4 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C ? (b) What is the y-component of the force exerted by A on C ? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.

From Fig. P-014, P is directed at an angle a from x-axis and the 200 N force is acting at a slope of 5 vertical to 12 horizontal. a. Find P and a if the resultant is 500 N to the right along the x-axis. b. Find P and a if the resultant is 500 N upward to the right with a slope of 3 horizontal to 4 vertical. c. Find P and a if the resultant is zero. 12 200 N Figure P-014

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A charge of +6.6 x 10-4 C is placed at the origin of a Cartesian coordinate system. A second charge of +8  x 10-4 C lies 20 cm above the origin, and a third charge of +3 x 10-4 C lies 20 cm to the right of the origin. Determine the direction of the total force on the first charge at the origin. Express your answer as a positive angle in degrees measured counter clockwise from the positive x-axis.