College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Two charged particles, held not too far from each other, are released. As they move, the electric force on each particle increases. So, the particles must have
A) the same mass
B) charges of opposite signs
C) the same size
D) charges of the same sign
E) impossible to answer without additional information
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- Two charges +2 µC and +8 µC are placed along the z axis, with the first charge at the origin (z =0) and the second charge at z = +1 m. Find the magnitude and direction of the net force on a -2 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the axis at x = -0.5 m: magnitude of force is is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +8 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) This problem is fully 2-dimensional. The charge at x = 1 m exerts force along y direction; the charge at the origin exerts force along the line connecting (x, y) = (0,0) and (z,y) = (1…arrow_forwardTwo charges +4 µC and +11 µC are placed along the x axis, with the first charge at the origin (x = 0) and the second charge at x = +1 m. Find the magnitude and direction of the net force on a -9 nC charge when placed at the following locations below. Overall Hint Review Section 5.3 Coulomb's Law. Use Coulomb's Law to calculate force due to each of two charges and add them together for the net force, minding the directions. For part (c), you will need to do the vector sum (more below). a. halfway between the two charges: magnitude of force is direction is Select an answer b. on the x axis at x = -0.5 m: magnitude of force is direction is Select an answer c. at the coordinate (x, y) = (1 m, 0.5 m) (half a meter above the +11 µC charge in a direction perpendicular to the line joining the two fixed charges): Hint for (c) Magnitude of force is degrees below -x axis. mN, and the direction is mN, and the mN, and thearrow_forward2. Three charges are arranged as shown in Figure. Find the magnitude and direction of the electrostatic force on the charge at the origin. [ Given Data Coulomb's constant, Ke = 8.99X10° Nm?/C²] q2 6.00nC 3.00nC 0.250m q1 0.150m -2.00nC q3 1. The electrostatic force F12 calculated (between q2 and q1)from the above diagram is = 2. The electrostatic force F23 calculated (between q2 and q3)from the above diagram is = u N 3. The Magnitude of the resultant force on q2 measured from the above diagram is = μΝ 4. The resultant direction O measured from the -x axis is = degreesarrow_forward
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