Two capacitors C, and C₂ are connected in series. a) Derive an expression for the equivalent capacitance C. b) Calculate the equivalent capacitance Ceq of two capacitors of values 2 µF and 4 μF in series. c) Write down the three capacitances C₁,C2 and Ceq in order of increasing capacitance.

C₂ U Example2: Find the total capacitance of the combination of capacitors shown in Figure. Assume the capacitances in Figure are known to three decimal places (C1=1.000 μF, C2=2.000 µF, and C3=5.000 µF).

Can you explain how the voltage drop across capacitor C2 is equal to 2V?

Three capacitors are connected in series. The equivalent capacitance of this combination is 3.27 µF. Two of the individual capacitances are 5.94 µF and 9.63 µF. What is the third capacitance (in µF)? 0.033 X HF Additional Materials M eBook A の stv W PDF MacBook Air 80 esc F2 F3 F4 FS F6 F7 F8 F9 * @ # 2$ % & 3 4 6. Q W E R T Y tab A S D F G J K caps lock C V VI * 00 つ エ B < CO

A voltage V is applied across capacitors C1, C2, and C3 in series. Calculate the equivalent capacitance, charge Q and voltage across C3 if:   V C1 C2 C3 4.80E+01 1.00E+00 2.00E+01 3.00E+01     Make sure to express your answer in scientific notation with 2 decimal points.

A system of capacitors is shown below. What is the equivalent capacitance of the system is the individual capacitors are; Express the answer in microFarads. For example, if the answer came out to be 4.98 X 10-7 F, this is the same as 49.8 microFarads. You would then answer with the numeric value of 4.98. C1 = 5.5 x 10-6 F C2 = 5.7 x 10-6 F C3 = 8 x 10-6 F C4 = 4.5 x 10-6 F C5 = 2.1 x 10-6 F

Consider the combination of capacitors below: C2 (a) If the capacitance of C, and C2 are the same, C3 has capacitance of 9.3 mF, and the capacitor network has equivalent capacitance of 3.0 mF, determine the capacitance of the unknown capacitors. Give your answer in units of mF.

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Find the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.)   (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor  µC on the left 37.80 µF capacitor  µC on the 31.80 µF capacitor  µC on the 6.00 µF capacitor  µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor  V on the left 37.80 µF capacitor  V on the 31.80 µF capacitor  V on the 6.00 µF capacitor  V

The figure below shows three capacitors with capacitances CA = 1.00 μF, CB = 2.10 μF, and Cc = 3.90 μF connected to a 6.00-V battery. CA CB QB = Qc = Cc (a) What is the equivalent capacitance of the three capacitors? UF + (b) What charge is stored in each of the capacitors? 6 X QA Your response differs from the correct answer by more than 10%. Double check your calculations. μC μC HC V V V (c) What is the potential difference across each of the capacitors? AVA = AVB = AVc =