Two capacitors are identical, except that one is empty and the other is filled with a dielectric (k = 3.4). The empty capacitor is connected to a 13-V battery. What must be the potential difference across the plates of the capacitor filled with a dielectric so that it stores the same amount of electrical energy as the empty capacitor? %3D V2 = i

b. Capacitor A and Capacitor B are two parallel plate capacitors. Capacitor B has twice the area and four times distance between plates of Capacitor A. (i) What is the ratio CB: CA, and (ii) What is the ratio of Energy stored UB:UA when the capacitors store the same charge on its plates?

A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.30 and whose dielectric strength is 1.20 x 108 V/m. The desired capacitance is 0.300 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m²

A parallel-plate capacitor is made of two square plates 20 cm on a side and 1 mm apart. The capacitor is connected to a 50-V battery. Hint # a. What is the energy stored in the capacitor? Energy stored in the capacitor is b. With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is c. This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is d. Comparing your results in (b) and (c) above, it makes sense that the energy stored in the capacitor- increases in (c), because the work done in separating the plates is stored as the electrostatic potential energy. In (b), why does the energy decrease even though work is done in separating the plates? E D Submit Question с 4 O The energy is not…