Two blocks with masses \(M_1) and \(M_21) are connected by a massless string that passes over a massless pulley as shown. (M_1) has a mass of (2.25 \text { kg}\) and is on an incline of \{\theta)_1=41.5^circl) with coefficient of kinetic friction ({\mu)_1=0.2051). (M_2\) has a mass of \ (6.75 \text{ kg)) and is on an incline of ( {\theta)_2= 35.5^\circl) with coefficient of kinetic friction ({\mu)_2= 0.1051). The two-block system is in motion with the block of mass (M_2 \\) sliding down the ramp. Find the magnitude (a_2 11) of the acceleration of \(M_21) down the incline. \\(a_2=\\) W Mext (m)/text(s)^{2} \\) M₁ M₂ Figure is not to scale.

icon
Related questions
Question

Plz solve within 40min ivill give positive feedback and vill give upvote thank u sir

Two
blocks with masses \(M_1) and \(M_2\) are connected
by a massless string that passes over a massless pulley as
shown. \(M_1\) has a mass of \(2.25 \text { kg}\) and is on an
incline of \({\theta)_1=41.5^circl) with coefficient of
kinetic friction ({\mu)_1 = 0.2051). \(M_2\) has a mass of \
(6.75 \text{ kg)) and is on an incline of \ {\theta)_2=
35.5^\circl) with coefficient of kinetic friction ({\mu)_2=
0.1051). The two-block system is in motion with the block of
mass \\( M_2 \\) sliding down the ramp.
Find the magnitude ( a_2 \\) of the acceleration of \(M_21)
down the incline.
\\(a_2=\\)
WCMtext(m) Atext(s)^{2} \\)
M₁
1₂
M₂
Figure is not to scale.
Transcribed Image Text:Two blocks with masses \(M_1) and \(M_2\) are connected by a massless string that passes over a massless pulley as shown. \(M_1\) has a mass of \(2.25 \text { kg}\) and is on an incline of \({\theta)_1=41.5^circl) with coefficient of kinetic friction ({\mu)_1 = 0.2051). \(M_2\) has a mass of \ (6.75 \text{ kg)) and is on an incline of \ {\theta)_2= 35.5^\circl) with coefficient of kinetic friction ({\mu)_2= 0.1051). The two-block system is in motion with the block of mass \\( M_2 \\) sliding down the ramp. Find the magnitude ( a_2 \\) of the acceleration of \(M_21) down the incline. \\(a_2=\\) WCMtext(m) Atext(s)^{2} \\) M₁ 1₂ M₂ Figure is not to scale.
Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

Blurred answer