Two blocks sitting on a rough horizontal surface are acted upon by a horizontal force F. The blocks have F masses of 8.00 kg (m¡) and 6.00 kg (m2) respectively. The coefficients of friction are H=0.450 and u=0.400 for the floor block interaction. m, m2 rough surfaces (a) Draw a complete free body diagram for each block; assume the blocks are not moving. (b) Determine the minimum value of the force F needed to put the blocks in motion. (c) If the applied force is 20% higher than the value you found in part (b), what will the acceleration of the blocks be?

A m1 = 5.01-kg block is placed on top of a m2 = 10.0-kg block (figure). horizontal force of F = 45.0 N is applied to the 10.0-kg block, and the 5.01-kg block is tied to the wall. The coefficient of kinetic friction between all moving surfaces is 0.182.(a)Draw a free-body diagram for each block and identify the action–reaction forces between the blocks.(b) Determine the tension in the string in magnitude of newtons.(c) Determine the magnitude of the acceleration of the 10.0-kg block.

Problem 8: Consider a bowling ball of mass M attached to two ropes. One rope is being pulled horizontally. The second rope is tied to the ceiling (see figure) and is at a 45° with respect to the ceiling.The bowling ball is stationary. T, M Please use the interactive area below to draw the Free Body Diagram for the bowling ball. A Add Force O Reset All T1 v 45 vx T1 Ftotal,x: + (pos) Ftotal,y: + (pos)

A 2.5 kg mass is initially at rest on a horizontal surface. An applied force acts in the +x direction resulting in a displacement of 1.50 m. If the speed of the mass is 4.00 m/s at the 1.50 m mark and the applied force is 22.0 N, what is the coefficient of kinetic friction?

The 1 kg standard body has an acceleration of 2.00 m/s² at 63° to the positive direction of the x axis. (e) What are the x and y components of the net force on it? x component N y component (b) What is the net force in unit-vector notation? F

A 3.45-kg object is moving in a plane, with its x and y coordinates given by x = 3t2 - 3 and y = 2t3 + 4, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.50 s.

Problem 6: Ablock with a mass of m = 43 kg rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction with a magnitude of F1 = 10.5 N. The second has a magnitude of F, = 22 N and acts on the body at an angle 0 = 19° measured from horizontal, as shown. m F, ©theexpertta.com Please select the correct free body diagram from the choices below. / Correct! Write an expression for the component of net force, Fnetx, in the x-direction, in terms of the variables given in the problem statement. Fnet x = cos(o) cos(e) sin(o) 8 9 HOME sin(e) tan(o) tan(0) 4 5 6 *1| 2 | 3 a F1 F2 END vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Write an expression for the magnitude of the normal force, FN, acting on the block, in terms of F2, g, and the other variables of the problem. Assume that the surface it rests on is rigid. Find the block's acceleration in the x-direction, ax, in meters per second squared.