Tuture is 220 R. B- The pressure in a vessel containing methane and water at 70°C is 10 atm. At the given temperature, the Henry's law constant for methane is 6.66 * 10 atm/mole fraction and vapor pressure of water at 70 °C is 0.3117 bar. Estimate the mole fraction of methane in the liquid. P₁ = 103 H = 4.66

Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the Henry's law constant is kH = 3.7 ×× 10–2 mol/(L • atm), and the mole fraction of O2 in the atmosphere is 0.209. Part1:Calculate the solubility (in M) of O2 in the blood of a climber on Mt. Everest, where Patm = 0.35 atm.___M Part2: Calculate the solubility (in M) of O2 in the blood of a scuba diver at a depth of 100 feet, where Patm = ~3 atm.___M

When 0.6403 of g calcium bromide is dissolved in 75.00 mL water, the solution temperature increses by 1.07 °C. Calculate the enthalpy of dissolution (ΔHrxn) for calcium bromide, in kj/mol.(Assume constant pressure is, 41.84j/g. °C as the specific heat capacity of the solution, and a density of 1.00 g/ml). Write out the equation.  I am confused on where to start with this problem.

From your data in Part 1 of the experiment, you calculate the natural log of the partial pressure of water and 1/T value in K for 5 points between 50°C and 80°C. You make a graph of In(P) vs. 1/T and determine that the slope of the linear line is -4800 K. Use this information to calculate AHvap of water. Make sure to use R = 8.314 J mol-1-K-1. Oa. 46.6 kJ/mol Ob. 0.578 kJ/mol Oc. 31.5 kJ/mol O d. 39.9 kJ/mol

Stuck on this, would appreciate help

One of the detrimental effects of the "thermal pollution" of water supplies is that a rise in temperature reduces the amount of dissolved oxygen available to fish. Using the information in the table of Henry's Law constants (KH) below, calculate how many litres of water a fish requires at 30.0°C to obtain the same amount of oxygen that it could obtain from 3.05 L of water at 25.0°C. TABLE HENRY'S LAW CONSTANTS (KH) IN AQUEOUS SOLUTION (M/Bar) Gas 0.0 °C 25 °C 30 °C N2 1.1 x 10-3 6.6 × 10-4 4.0 × 10-4 O2 2.5 x 10-3 1.3 x 10-3 8.8 x 10-4 CO 1.6 x 103 9.5 x 104 4.4 x 10-4 Ar 2.5 x 10-3 1.5 x 10-3 1.0 x 10-3 Не 4.1 x 10-4 3.8 x 10-4 3.8 x 10-4 CO2 7.7 x 10-2 3.4 x 10-2 1.6 x 10-2 i 1.7