Tutorial Exercise A man standing 1.61 m in front of a shaving mirror produces an inverted image 16.9 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size? Step 1 When the man stands 1.61 m in front of the mirror, the object is located at a distance p = +1.61 m 161 cm. We are given that a real image is formed at the image distance of q = +16.9 cm. We find the focal length f of the mirror from the mirror equation, 1/f 1/p+1/q. Solving for the focal length, we obtain the following. pq p+q For the product in the numerator, pg= cm², and for the sum in the denominator, cm, and thus for the focal length, we obtain Submit pq p+q Skip (you cannot come back) cm.

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REFLECTION & REFRACTION Tutorial Questions 1. Her eye at point P looks into the mirror. Which of the numbered cards can she see reflected in the mirror? S Mirror 2. Cowboy Joe wishes to shoot his assailant by ricocheting a bullet off a mirrored metal plate. To do so, should he simply aim at the mirrored image of his assailant? Explain. 3. Why is the lettering on the front of some vehicles "backward"? ЭOVAJU&MA 4. Why is it difficult to see the roadway in front of you when driving on a rainy day? 5. What must be the minimum length of a plane mirror in order for you to see a full view of yourself? 6. What effect does your distance from the plane mirror have in the above answer? (Try it and see!) 7. If you were spearing a fish, would you aim above, below, or directly at the observed fish to make a direct hit? If instead you zapped the fish with a laser, would you aim above, below, or directly at the observed fish? Defend your answers. - [Week 5 ends here] --- 8. If the fish in the…

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I have four resistances having values of (A)7.5Kilo ohm, (B)5.5 kilo ohm, (C)4.5Kilo ohm and (D)2.5 kilo ohm and I want 5000 ohm. What will be the combination? (A series D) parallel (B series C) (A series B) parallel (C series D) (A parallel B) series (C parallel D) (A parallel D) series (B parallel C)

Part A A ray of light impinges on a mirror as shown in (Figure 1), 0 = 25°. A second mirror is fastened at 90° to the first. %3D At what angle above horizontal does the ray emerge after reflecting from both mirrors? Express your answer in degrees. ΑΣφ O = %3D Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Figure Provide Feedback

b. Explain the concept of the following and how they occur in our daily lives (Exampl es should not be related to lecture notes) i. Newton's First Law of Motion ii. Newton's Third Law of Motion iii. Refraction iv. Concave Mirror V. Convex Mirror

Part A A small object is 25.0 cm from a diverging lens as shown in the figure(Figure 1). A converging lens with a focal length of 12.4 cm is 30.0 cm to the right of the diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the converging lens. What is the focal length of the diverging lens? ? f = cm Submit Request Answer Figure 1 of 1 < Return to Assignment Provide Feedback 30.0 cm 17.0 cm- 25.0 cm

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can someone please help me with this physics question