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- When a person feels that he is about to fall, he will often put out his hand to try to break the fall. Explain why this natural reaction usually leads to bruises or minor broken bones such as in the wrists instead of major broken bones such as the skull.When you bend your knee, the quadriceps muscle is stretched. This increases the tension in the quadriceps tendon attached to your kneecap (patella), which, in turn, increases the tension in the patella tendon that attaches your kneecap to your lower leg bone (tibia). Simultaneously, the end of your upper leg bone (femur) pushes outward on the patella. Shown is how these parts of a knee joint are arranged. What size force does the femur exert on the kneecap if the tendons are oriented as in the figure and the tension in each tendon is 60 N?Please answer it within 30 minutes. I will upvote! Problem: A useful instrument for evaluating fibromyalgia and trigger-point tenderness is the doloriometer (or algorimeter). This device consists of a force meter attached to a circular probe that is pressed against the skin until pain is experienced. If the reading of the force meter is 14.0 N (3.15 lb ), and the diameter of the circular probe is 1.44 cm , what is the pressure applied to the skin? Give your answer in pascals.
- Problem 7: Two muscles in the back of the leg pull upward on the Achilles tendon, as F,(200 N) F,(200 N) shown in the figure. (These muscles are called the medial and lateral heads of the gastrocnemius muscle.) 20 20 Find the magnitude, in newtons, of the total force on the Achilles tendon. F =2) A student’s head is bent over her physics book. The head weighs P = 24.6 N and is supported by the muscle force F→mF→m exerted by the neck extensor muscles and by the contact force F→cF→c exerted at the atlantooccipital joint. Given that the magnitude of F→mF→m is 60.0 N and is directed 35.0° below the horizontal. a.) Find the magnitude of the contact force F→cF→c . b.)Find the direction of the contact force Fc−→Fc→ . If the direction is below the horizontal, enter a negative value.A person places his hand palm downward on a scale and pushes down on the scale until it reads 96.0 N. The triceps muscle is responsible for this arm extension force. Find the force exerted by the triceps muscle. The bottom of the triceps muscle is 2.50 cm to the left of the elbow joint, and the palm is pushing at approximately 29.0 cm to the right of the elbow joint. P 96.0 N 2.50 cm and Q = 29.0 cm. where P =
- I am needing help on parts (i) and (j) please4. The Achilles tendon experiences an upward pull from two muscles situated at the back of the leg, known as the medial and lateral heads of the gastrocnemius muscle. Calculate the magnitude of the total force acting on the Achilles tendon. F(250N) F(220 N) 20 20When throwing a football you are always instructed to follow-through. What is the advantage of this? You are also instructed to stand with your feet about shoulder-width apart. What is the advantage of this?
- The length of the Achilles tendon increases 0.500 cm when the force exerted on it by the muscle increases from 3198 N to 4769 N.African elephants are the largest land animals. They consume approximately 10% of their body weight in food each day, which for an adult male, can be 1000 lb. of vegetation! Their diet consists mostly of grasses, bamboo, tree bark, and fruit. They also like to dine on tree leaves. To reach them, they often stand up on their hind legs and extend their trunks (see the figure). The elephant in the figure is in equilibrium. The location of the elephant's center of mass is shown, and the axis of rotation has been chosen to correspond to the hip joint. The forces in the elephant's free-body diagram are shown, and there is a static friction force between the elephant's back feet and the ground. Use the following information and calculate the magnitude of the tension in the elephant's trunk T (m = 4540 kg, FN = rfs = 133 cm, rcg = 76.0 cm, r = 229 cm). Number +x Axis of rotation Units 60 165 30 W TTFN cg 10° Michael Poliza/Caters News Agency10.0 U 1752 (O RI = 4L A3,4= Rgt Ry %3D Rz = 52 R 3,4,5 = 6.32 R34 %3D R2,3,4,9= Rz + R3,4,5 = 1.32 Ry= 92 Req = (* 2 2.95 to k5 = 102 R2,3,4,5 R P