Triple DES's middle piece does not involve encryption but rather decryption.
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Triple DES's middle piece does not involve encryption but rather decryption.
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- Instead of encryption, the middle component of triple DES is designed to do decryption.Encoding a message starts with assigning each letter of the alphabet with a positive integer using a specific pattern, thus rewriting the original message as a list of numbers instead of words. Decoding a message is the process that "undoes" the encoding process. Assume that the table below was used to encode an important secret message. F-6 G- 7 Z- 26 Blank - 27 P- 16 U- 21 V– 22 W- 23 х-24 Y- 25 А-1 К-11 В -2 С -3 D- 4 E-5 Q- 17 R- 18 H-8 |- 9 J- 10 L- 12 М-13 N- 14 о- 15 S- 19 т- 20 You intercepted the following encoded message from Boris and Natasha. 25 19 19 30 41 17 15 26 27 41 15 28 18 41 18 29 41 34 22 19 41 27 15 34 22 You do not know the encoding or decoding function, but you know this message consists of 6 words. Using the encoding system described above, answer the following questions. Analysis 1. From previous work with Boris and Natasha, you know that their encoding and decoding functions are always linear and have 1 as the coefficient of x. Write the general form of the…Encoding a message starts with assigning each letter of the alphabet with a positive integer using a specific pattern, thus rewriting the original message as a list of numbers instead of words. Decoding a message is the process that "undoes" the encoding process. Assume that the table below was used to encode an important secret message. 5. A- 1 В - 2 С - 3 D- 4 E- 5 F-6 К-11 L-12 М-13 N-14 O-15 P-16 Q-17 R-18 S- 19 т-20 U-21 V- 22 W-23 Z-26 Blank - 27 G- 7 Н-8 |-9 J- 10 X-24 Y-25 nut You intercepted the following encoded message from Boris and Natasha.oy 25 19 19 30 41 17 15 26 27 41 15 28 18 41 18 29 41 34 22 19 41 27 15 34 22 You do not know the encoding or decoding function, but you know this message consists of 6 words. Using the encoding system described above, answer the following questions. Analysis 1. From previous work with Boris and Natasha, you know that their encoding and decoding functions are always linear and have 1 as the coefficient of x. Write the general form of the…
- Describe the process of how to solve the substitution cipher below and solve it: ZFSZB YESUK SQYDJ SQGVK SGZBJ WBSWG IZXWF UVDYZ TZVKW JJSUQ JJTDQ KCSPI QKQFP FZYBW FPWFU QYWIC SYZFW YInstead of encryption, the middle component of triple DES is decryption.The middle component of triple DES is decryption, not encryption.
- Suppose you have a block cipher with block length of 32 bytes (256-bits). Suppose you want to encrypt a message that is 747 bytes long. Using CBC mode and ciphertext stealing, how long will the ciphertext be? That is, how many bytes will be in the ciphertext?Cypher block chaining and cypher feedback mode may be compared with regards to the number of encryption operations needed to transmit a large file.How much more efficient is one option than the other?Assume you are using any correct plaintext padding method, such as those described in lecture, with a 128-bit (16-byte) block cipher. If you are sending a message that is 184 bytes long, how many padding bytes would you need to add? Justify your answer. For the remaining questions, consider a 4-bit block cipher, described in hexadecimal by the following table: Plaintext Ciphertext Plaintext Ciphertext 0 a 8 e 1 c 9 d 2 f a 0 3 6 b 7 4 3 c 5 5 8 d b 6 4 e 9 7 2 f 1 You can think of this as a simple substitution cipher for hexadecimal digits. There is no “key” other than the table itself.
- 1. Perform encryption and decryption using the RSA algorithm for p=3, q=5, e-7, d=3, M=13, where p, q are two prime numbers used to generate modulus n, e is the public key component, d is the private key component and M is the message.Answer the following question: Give the pros and cons for block size as it relates to the Feistel CipherConsider a 64 bit Block Encryption algorithm E. Suppose you have encrypted a 64 byte message Mı, M2, .. M64. Show / explain using diagrammatic forms how you would decrypt the message using CBC and OFB-16. Use an 8 byte IV: I1, I2, ... Is.