Triangular or “V” shaped channel with the sides inclined at an angle, θ = 60O from the horizontal and the depth, d= 0.75m from the apex, find the hydraulic radius

Hydraulic structure Two concrete pipes (n = 0.01) must carry the flow from an open channel half square section 2m wide and 1m deep (n = 0.01168) The slope of both structures is (0.0009). Determine the diameter of the pipes.

Prob. # 5 (a): In a partially flowing channel having a isosceles-triangular cross section as shown below (Figure 5a), the rate of flow can be expressed as Q=KAR 2³, where k is a constant and A and R are respectively cross sectional area and the hydraulic radius. Determine the depth at which the discharge is maximum. For the channel, A= [B - (h/√3)]h, and P= B + (4h/3). 60 60° Figure section. 5a-Triangular channel cross

The elbow flow passage volume is 0.37 m3 between sections 1 and 2. The flow rate is 0.90 m3/s and the elbow inlet and outlet pressures are 200 kPa and 130 kPa. Consider the elbow weight is negligible. Calculate the horizontal and vertical anchoring forces to hold the elbow in place.    my results were Frx = 132.8kPa Fry = 76.7kPa