Triangle similarity can be used to prove that the midsegment of a triangle is parallel to its base.Complete the proof by providing the missing reasons for each statement.AD8CImage created with GeoGebraGiven: AABC and AADE DE is a midsegmentProve: DE || BC AB = AD + ADAC = AE + AEAB= 2(AD)AC = 2(AE)AD=AB2AC 1-121-AB andReason 3Simplify by combining like termsDivision property of equality

Converse of corresponding angle theoremIf two lines and a transversal form corresponding angles…

Triangle similarity can be used to prove that the midsegment of a triangle is parallel to its base. Complete the proof by providing the missing reasons for each statement. E Image created with GeoGebra Given: AABC and AADE DE is a midsegment Prove: DE || BC

Triangle similarity can be used to prove that the midsegment of a triangle is parallel to its base. Complete the proof by providing the missing reasons for each statement. E Image created with GeoGebra Given: AABC and AADE DE is a midsegment Prove: DE || BC

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter4: Quadrilaterals

Section4.3: The Rectangle, Square, And Rhombus

Problem 42E: a Argue that the midpoint of the hypotenuse of a right triangle is equidistant from the three...

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Question

Triangle similarity can be used to prove that the midsegment of a triangle is parallel to its base.
Complete the proof by providing the missing reasons for each statement.
A
D
8
C
Image created with GeoGebra
Given: AABC and AADE DE is a midsegment
Prove: DE || BC

AB = AD + AD
AC = AE + AE
AB= 2(AD)
AC = 2(AE)
AD=
AB
2
AC 1-
1
2
1-
AB and
Reason 3
Simplify by combining like terms
Division property of equality

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