Trials 1 2 3 Volume of aliquot of standard CaCO, solution 25.00 (ml) 25.00 25.00 Volume of titrant, EDTA (ml) 23.20 23.50 23.34 Titer (mg CaCO,/mL EDTA) Trial 1 Trial 2 Trial 3

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Chapter1: Chemical Foundations
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Solve for titer. Pls show me the solution or step by step process so I can follow. Thank you

Trial 1
2.513 x 10-4 mol EDTA
Molanity of EDTA
0.02320 L
= 0. 01083 M EDTA
Trial 2
2)
Molarity
2.513 x 10-4 mol EDTA
of EDTA
0. 02350 L
= 0.01069 M EDTA
Trial 3
9 =
Molaity of EDTA
2.513 x 10-4 mol EDTA
0. 02534 L
0.61077 M EDTA
Transcribed Image Text:Trial 1 2.513 x 10-4 mol EDTA Molanity of EDTA 0.02320 L = 0. 01083 M EDTA Trial 2 2) Molarity 2.513 x 10-4 mol EDTA of EDTA 0. 02350 L = 0.01069 M EDTA Trial 3 9 = Molaity of EDTA 2.513 x 10-4 mol EDTA 0. 02534 L 0.61077 M EDTA
Trials
1
2
3
Volume of aliquot of standard CaCO, solution 25.00
25.00 25.00
(ml)
Volume of titrant, EDTA (ml)
23.20
23.50 23.34
Titer (mg CaCo,/mL EDTA)
Trial 1
Trial 2
Trial 3
Transcribed Image Text:Trials 1 2 3 Volume of aliquot of standard CaCO, solution 25.00 25.00 25.00 (ml) Volume of titrant, EDTA (ml) 23.20 23.50 23.34 Titer (mg CaCo,/mL EDTA) Trial 1 Trial 2 Trial 3
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