Translate the following statements using probability notation. Use X as the random variable. The probability of X being no less than a: P(X > a) P(X < a) P(X ≤ a) P(X ≥ a) P(X = a) The probability of X being more than a: P(X = a) P(X ≥ a) P(X > a) P(X < a) P(X ≤ a) The probability of X being exactly a: P(X < a) P(X ≥ a) P(X ≤ a) P(X = a) P(X > a)

Insurance: An insurance company sells a 1-year term life insurance policy to an 79-year-old woman. The woman pays a premium of $1800. If she dies within 1 year, the company will pay $39,000 to her beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 79-year-old woman will be alive 1 year later is 0.9561. Let X be the profit made by the insurance company. Part 1 of 2 (a) Find the probability distribution. The probability distribution is X -37200 1800 P(x) 0.0439 0.9561 Alternate Answer: X P(x) Part: 1 / 2 Part 2 of 2 - 37,200 1800 0.0439 0.9561 (b) Find the expected value of the profit. Expected value of the profit is S X 00

Find the probability ​P(Ec​) if ​P(E)=0.17.

The probability distribution given below represents the projected profit (in thousands of dollars) earned from a business over a year.   Profit (x) in thousands of dollars f(x) -100 0.05 -50 0.15 0 0.30 50 0.35 100 0.12 200 0.03   a.) What is the probability that the business will operate at a loss for the year?     b.) What is the probability that the business will break even?     c.) What is the expected value for profit? Fill out the table below to help you calculate the value.

Insurance: An insurance company sells a 1-year term life insurance policy to an 80-year-old woman. The woman pays a premium of $4000. If she dies within 1 year, the company will pay $53,000 to her beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 80-year-old woman will be alive 1 year later is 0.9259. Let X be the profit made by the insurance company. Part: 0 / 2 Part 1 of 2 (a) Find the probability distribution. The probability distribution is X P(x) 4000 ☑

A basketball player makes 70% of her free throws. When fouled, she gets to take two free throws. Let X represent the number of free throws made in two tries. The probability distribution for the number of free throws she makes in two attempts is summarized in the following table: Number of free throws made Probability P(X 1) P(X ≤1) 0 O P(X ≥ 1) 0.09 1 The probability statement representing that she makes at least one free throw is expressed as 0.42 2 0.49

Insurance: An insurance company sells a 1-year term life insurance policy to an 84-year-old woman. The woman pays a premium of $1400. If she dies within 1 year, the company will pay $46,000 to her beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 84-year-old woman will be alive 1 year later is 0.9714. Let X be the profit made by the insurance company. Part: 0 / 2 Part 1 of 2 (a) Find the probability distribution. The probability distribution is x 1400 X P(x)