Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Now 6н 154-145=0
с
6x+54 = 45
2
Thus;
54 : -45-6к
-96 x →
5
The slope of our first line is m =
2
Thus
-45-6X
5
Perpendicular lines have negative reciprocal slopes
Thus; negative reciprocal of
10 =
(20) +b
: 10 = 100 + b
6
5 is slope of our line
The equation of line passing through point (20, 10).
So substitute given points in equation y= 5x +b -0
b = 10-100
6
Co
--x-9
6
7
⇒ y = 58-40
6
जाने
is 5
0167
60-100
6
=-900
-५०
put value of 'b' in 1 we get; y = 5x-20
6Y = 5X-40
69.
7
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Transcribed Image Text:Now 6н 154-145=0 с 6x+54 = 45 2 Thus; 54 : -45-6к -96 x → 5 The slope of our first line is m = 2 Thus -45-6X 5 Perpendicular lines have negative reciprocal slopes Thus; negative reciprocal of 10 = (20) +b : 10 = 100 + b 6 5 is slope of our line The equation of line passing through point (20, 10). So substitute given points in equation y= 5x +b -0 b = 10-100 6 Co --x-9 6 7 ⇒ y = 58-40 6 जाने is 5 0167 60-100 6 =-900 -५० put value of 'b' in 1 we get; y = 5x-20 6Y = 5X-40 69. 7
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