College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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The figure below shows a fisherman with a fishing pole that makes an angle of 20.0° above the horizontal. The distance from the fisherman's hand to the tip of the pole is L = 1.89 m. A fish is on the line, and it pulls the line with a force of F = 119 N at an angle 37.0° below the horizontal. What is the magnitude of the torque (in N · m) exerted by the fish about an axis perpendicular to the page and passing through the fisherman's hand?
Expert Solution
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Step 1
Torque is equal to cross product of force and distance.
To calculate force ... first resolve force in x and y direction components....here in this case let x axis is along the line L ....and y acis is perpendicular to it.....
Fx = Fcos(theta)
Fy = Fsin(theta)
Here theta is the the angle between Line L and direction of force F
Theta = 20+37 = 57
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