Please answer this. I will surelu upvote!!! Torque due to Unequal ForcesTorqueHanging LoadPosition onMomentMass (g) Weight (N) | Meterstick (cm) | Arm (cm) | Magnitude (N·m) | Direction (CW/CCW)CCWm₁(A)T1(B)(C)(E)(G)m₂(D)(F)x2Percent Difference0.00%Center of Gravity: 50 cmRefer to the table above. What mass m₂ should be placed at x₂=91.6 cm in order to balance a torque of 0.1776 N·m with counterclockwise rotation due to m₁?O 43.6 gO 216gO 19.8 gO 427 g

center of gravity = 50 cm= 0.50 m position of m2 = 91.6 cm = 0.916 mtorque to be balanced = 0.1776…

Torque due to Unequal Forces Torque Hanging Load Position on Moment Mass (g) Weight (N) | Meterstick (cm) | Arm (cm) | Magnitude (N-m) | Direction (CW/CCW) CCW m₁ (A) (B) (C) T1 (E) (F) m₂ (D) Percent Difference 0.00% Center of Gravity: 50 cm Refer to the table above. What mass m₂ should be placed at x₂=91.6 cm in order to balance a torque of 0.1776 N-m with counterclockwise rotation due to m₁? O 43.6 g O 216g O 19.8 g O 427 g

Torque due to Unequal Forces Torque Hanging Load Position on Moment Mass (g) Weight (N) | Meterstick (cm) | Arm (cm) | Magnitude (N-m) | Direction (CW/CCW) CCW m₁ (A) (B) (C) T1 (E) (F) m₂ (D) Percent Difference 0.00% Center of Gravity: 50 cm Refer to the table above. What mass m₂ should be placed at x₂=91.6 cm in order to balance a torque of 0.1776 N-m with counterclockwise rotation due to m₁? O 43.6 g O 216g O 19.8 g O 427 g

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 82A

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