Tom enlists the help of his friend John to move his car. They apply forces to the car as shown in the diagram. Here IF₁1 = 442 N, IF₂1 = 340 N and friction is negligible. Mass of the car = 3.50 x 10³ kg, 0₁ = 12.0°, and 2₂ = 25.0°. The diagram below shows the top view of the car which is in the x-z plane (horizontal plane). T F₁ (a) Find the resultant force exerted on the car. (Express your answer in vector notation.) Fnet = 530.92k + 170.56j X Did you consider the components of the forces in the x and z directions? Review rules for vector addition. N (b) What is the acceleration of the car? (Express your answer in vector notation.) a= 0.223 X How is the net force on an object related to its acceleration? m/s²2

A box is motionless, sitting on a ramp with an incline of 0 =54.4 ° being pulled in the direction up the ramp by a spring with a spring constant of k=150 N/m that is stretched x=6.4 m. The coefficient of friction between the ramp and the box are u s=0.53 and u k=0.15 and the friction force is going down the ramp. What is the mass of the box? Solve symbolically: Solve numerically: m= Units: If the box starts moving up a ramp with an acceleration of a=2.41 m/s, what is the new length that the spring will stretch? Solve symbolically: Solve numerically: Units:

At the instant of the figure, a 1.00 kg particle P has a position vector 7 of magnitude 5.40 m and angle 01 = 41.0° and a velocity vector v of magnitude 4.50 m/s and angle 62 = 32.0°. Force F ,of magnitude 6.20 N and angle 03 = 32.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the angular momentum of the particle and (b) the torque acting on the particle? F (a) Number i Units (b) Number i Units

A conical pendulum has length l and the angle made by the string with vertical is e = 35° . The mass of the object is m=124 g. If the speed of the object is v=3.9m/s find the length of the string. Take g=10Om/s2. Round your answer to one decimal place.