toddler makes a bee-line for the road travelling from the edge of a sandbox 7.60 m away from the road at a constant speed of 0.540 m/s. Their parent, initially reading by the sandbox, assesses the situation 3.10 seconds later and moves with a constant acceleration of 0.900m/s^2 to catch the child. How far from the road, in meters, is the toddler when their adventure is interrupted?

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pls illustrate the graph. I already have found the solution for this question but I need the graph ASAP!!     A small asteroid strikes the surface of Mars andcauses a rock to fly upward with a velocity of 26 m/s[52deg above the horizontal]. The rock rises to amaximum height and then lands on the side of a hill12 m above its initial position. The acceleration due togravity on the surface of Mars is 3.7 m/s2/6 A full diagram must be shown in your solution(a) Calculate the maximum height of the rock.(b) Determine the time that the rock is in flight.(c) What is the range of the rock?

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V/A Spelunlier drops astone off of aclıff inadarl cave at the instmat he starts his stonwatch.Hehears the stone hit water 1.3secends utter he releases it. How fe below is the water? Give yor mswer in feed. A27.2 ft B 8.3 t7 ८घ दा cis.4 ft D)9.0 t# 3D. 2 ft

A book slides off a horizontal table top with a speed of 1.10 m/sm/s. It strikes the floor after a time of 0.410 ss. Ignore air resistance. I got the 1st 2 questions and need help w the last 4 if possible. Thanks!! I wrote my answers to the first 2. 1. Find the height of the table top above the floor. =.825m 2. Find the horizontal distance from the edge of the table to the point where the book strikes the floor. = .451m 3. Find the magnitude of the horizontal component of the book's velocity just before the book reaches the floor. =?? 4. Find the magnitude of the vertical component of the book's velocity just before the book reaches the floor.=?? 5. Find the magnitude of the book's velocity just before the book reaches the floor.=?? 6. Find the direction of the book's velocity just before the book reaches the floor.=??

Problem 1 A cannon ball on the ground is fired at 35 with an initial velocity of 250 m/s. a. How long will it take to hit the ground? b. How far from the cannon ball will it hit the ground? c. Compute for maximum height to be reached by the cannon ball. Given: V. - 250 m/s 35 g- 9.8" Solution: a. The time of flight of the cannon ball 2v, sin 500m/s(sin 35°) 500m/s(0.57) _ 28Sm/s = 29.08s 9.8m/x 9.8m/s 9.8m/s b. The range of the cannon ball v, sin 0 (250m/s) 2 sin 35° 62500m2/s 2(0.57) 9.8m/s R 9.8m/ s 62.500m /s(0.9397) 58,730.79m /s? 9.8m/s 5,992.94m 9.8m/s c. The maximum height that the cannon ball reached v sin 0 (250m/s)²(sin 35")(sin35") 62.500m /s²(0.57) 2(9.8m/s) Утах 28 19.6m/s 62,500m² /s²(0.32899 20,561.87m /s- 1,049.08m 19.6m/s 19.6m/s This time, it's your turn to solve the next problem. Problem 2 An arrow is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal. 10 a. How long will it take to hit the ground? b. How far from the…

An attacker at the base of a castle wall 3.65 m high throws a rock straight up with speed 7.4m/s from a height of 1.55m above the ground. a) will the rock reach the top? b) if so what is its speed at the top? if not, what initial speed must it have to reach the top? c) find the change in speed of a rock thrown straight down from the top of the wall at an initial speed of 7.4 m/s and moving between the same two points. d) does the change in speed of the downward moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? e) why does this agree or not agree.

A ball is dropped from a height of 6m above the ground. The velocity of the ball when reaching the ground is O a 9.8 m/s ut of O b.10.84 m/s estion OG 7.66 m/s Od. 10.84 m/s