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Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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![To test this series for convergence:
\[
\sum_{n=1}^{\infty} \frac{3^n - 2}{7^n}
\]
You could use the Limit Comparison Test, comparing it to the series \(\sum_{n=1}^{\infty} r^n\) where
\[
r = \frac{1}{7}
\]
(There is an error with a red "x" indicating a mistake or problem in the calculation or setup related to the value of \(r\).)](https://content.bartleby.com/qna-images/question/62b092f3-63db-4d93-982f-67d0473d8e68/0d32c50d-eab9-4923-918b-6ef3b9c5116e/924saxa_thumbnail.jpeg)
Transcribed Image Text:To test this series for convergence:
\[
\sum_{n=1}^{\infty} \frac{3^n - 2}{7^n}
\]
You could use the Limit Comparison Test, comparing it to the series \(\sum_{n=1}^{\infty} r^n\) where
\[
r = \frac{1}{7}
\]
(There is an error with a red "x" indicating a mistake or problem in the calculation or setup related to the value of \(r\).)
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- Consider the following series: 4 – 3/k k2 - 2k A k=3 (a) Can the Integral Test be used for this series? Explain in detail your answer. Show all your steps. (b) If the answer in (a) is yes, then use the Integral Test to determine if this series is convergent or divergent. Otherwise. use the Absolute Convergence Test Show al your steps. auired: Upload your work to SLATEa nd sut th designated boxes belowarrow_forwardTo test this series for convergence n=1 52-3 6n You could use the Limit Comparison Test, comparing it to the series where r Completing the test, it shows the series: O Diverges Converges n=1arrow_forward4arrow_forward
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