To test the hypothesis that the population meanmu 17.4, a sample size n=11 yields a samplemean 18.641 and sample standard deviation1.905. Calculate the P-value and choose thecorrect conclusion.Your answer:OOOThe P-value 0.009 is not significant and sodoes not strongly suggest that mu>17.4.The P-value 0.009 is significant and sostrongly suggests that mu>17.4.The P-value 0.022 is not significant and sodoes not strongly suggest that mu>17.4.The P-value 0.022 is significant and sostrongly suggests that mu>17.4.The P-value 0.004 is not significant and sodoes not strongly suggest that mu>17.4.The P-value 0.004 is significant and sostrongly suggests that mu>17.4.The P-value 0.028 is not significant and sodoes not strongly suggest that mu>17.4.The P-value 0.028 is significant and sostrongly suggests that mu>17.4.

From the provided information, Sample size (n) = 11 Sample mean (x̄) = 18.641 Sample standard…

Answered: To test the hypothesis that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 46 adult coyotes from Northern Minnesota showed the average age to be sample mean of 2.05 years. The population standard deviation is known to be o = 1.13 years. However, it is thought that the average age of coyotes is u = 1.75 years. Test to see if the coyotes in Northern Minnesota live longer than the national average of 1.75 years. Use 0.03 level of significance. What are the hypotheses? A: Ho µ= 1.75 years vs HA µ> 1.75 years B: Ho µ= 1.75 years vs HA H 2.05 years D: Ho µ = 2.05 years vs HA u< 2.05 years O A D O O
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You wish to test the following claim (HaHa) at a significance level of α=0.05 Ho:μ=59.9 Ha:μ>59.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=93n=93 with mean M=62.6M=62.6 and a standard deviation of SD=9.4SD=9.4.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. The sample data support the claim that the…
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1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550 and a standard deviation of 170. A batch of wire is made by a new process, and a random sample consisting of 25 measurements gives an average strength of 1316. Assume that the standard deviation does not change. Is there evidence at the 1% level of significance that the new process gives a larger mean strength than the old? To answer this question, the null hypothesis could be stated as A. μ= 1550 psi B. μ> 1550 psi C.µ + 1550 psi D. μ< 1550 psi
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suppose that for a sexually active male drosophila fruit fly in a particular genetics lab the population mean lifespan is 38.9 days with a population standard deviation of 12.0 days when she experimentally removed all females from a simple random sample of 24 this drosophila flies in her lab a researcher in the slab found that 24 sexually inactive males had a mean lifespan of 62.5 days with a standard deviation of 14.1 days answer the questions below about the experiment and about testing weather sexual activity affects how long males Drosophila live. How do you find the Critical Value? How do you find theP-Value? reject or fail to reject the null hypothesis?

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